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LordVictorius

  • 3 years ago

Prove that 1+sec^2x*sin^2x=sec^2x

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  1. geerky42
    • 3 years ago
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    Remember, \(\sec^2x = \dfrac{1}{\cos^2 x}\)

  2. LordVictorius
    • 3 years ago
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    How does that help me?

  3. geerky42
    • 3 years ago
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    Replace it then simplify. You will see what I mean.

  4. geerky42
    • 3 years ago
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    in 1+sec^2x*sin^2x, of course.

  5. LordVictorius
    • 3 years ago
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    I got it, sorry for not reporting back to you.

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