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Sunshine447

  • 2 years ago

Look at the figure shown below.

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  1. Sunshine447
    • 2 years ago
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    Which statement must be true to prove that segment DE is parallel to segment CA?

  2. Sunshine447
    • 2 years ago
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    4 : EA = 1 : DC 2 : DC = 5 : EA 3 : EA = 2 : DC 1 : DC = 2 : EA

  3. Sunshine447
    • 2 years ago
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    @phi hopefully this will be the last question I need help with...

  4. phi
    • 2 years ago
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    I can't see your image.

  5. Sunshine447
    • 2 years ago
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  6. Sunshine447
    • 2 years ago
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    now can you?

  7. phi
    • 2 years ago
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    if DE is || to CA then the sides of the triangle are transversals |dw:1359074409155:dw| if the lines are parallel then the marked angles are equal "corresponding angles" of a transversal if the angles are all the same, the top little triangle is similar to the big triangle. that means you want the sides to be in proportion

  8. Sunshine447
    • 2 years ago
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    okay,but how do we make the sides proportionate?

  9. Sunshine447
    • 2 years ago
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    @phi ?

  10. phi
    • 2 years ago
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    for example you can say the legs of the little triangle on top are in the ratio of 16/24 or simply 2/3 the legs of the big triangle are in the same ratio BC/BA but that isn't in any of the choices also, the segments, DC/EA are in proportion \[ \frac{2}{3} = \frac{DC}{EA} \] that looks promising but it's not in the same form as your choices we can reorder things, by first cross multiplying 2*EA = 3*DC now divide by EA : 2= DC * 3/EA divide by DC 2/DC = 3/EA

  11. phi
    • 2 years ago
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    you can write 2/DC = 3/EA this way 2: DC = 3:EA or 3 : EA = 2 :DC

  12. Sunshine447
    • 2 years ago
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    okay! so it's C?

  13. phi
    • 2 years ago
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    yes.

  14. Sunshine447
    • 2 years ago
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    Oh my gosh @phi , I have no clue how, but you make it possible for me to understand math! Thanks sooooo much for ALL the help you've given me! :)

  15. phi
    • 2 years ago
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    yw

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