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Solve the equation. Identify any extraneous solutions.
sqrt a = 8
A. –64 is a solution of the original equation. 64 is an extraneous solution.
B. 64 is a solution of the original equation.
C. 64 is a solution of the original equation. –64 is an extraneous solution.
D. no solution <<<
 one year ago
 one year ago
Solve the equation. Identify any extraneous solutions. sqrt a = 8 A. –64 is a solution of the original equation. 64 is an extraneous solution. B. 64 is a solution of the original equation. C. 64 is a solution of the original equation. –64 is an extraneous solution. D. no solution <<<
 one year ago
 one year ago

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tyteen4a03Best ResponseYou've already chosen the best response.1
To get rid of square roots, square both sides.
 one year ago

precalBest ResponseYou've already chosen the best response.1
dw:1359074224200:dwdo just like tyteen4a03 suggested
 one year ago

tyteen4a03Best ResponseYou've already chosen the best response.1
@Hally The answer is B. Whenever you are raising a number to an even number, the negative sign disappears. (If you need proof just ask.)
 one year ago

HallyBest ResponseYou've already chosen the best response.0
i know that part thanks! :)
 one year ago

precalBest ResponseYou've already chosen the best response.1
dw:1359074661681:dwquestion is, is this true?
 one year ago

HallyBest ResponseYou've already chosen the best response.0
no. sqrt 64 = 8 and 8 is not equal to 8
 one year ago

precalBest ResponseYou've already chosen the best response.1
then that means that the solution is extraneous
 one year ago

HallyBest ResponseYou've already chosen the best response.0
oh. so the answer is "64 is a solution of the original equation. –64 is an extraneous solution" .... right?
 one year ago
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