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Hally

  • 2 years ago

Solve the equation. Identify any extraneous solutions. sqrt a = -8 A. –64 is a solution of the original equation. 64 is an extraneous solution. B. 64 is a solution of the original equation. C. 64 is a solution of the original equation. –64 is an extraneous solution. D. no solution <<<

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  1. tyteen4a03
    • 2 years ago
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    To get rid of square roots, square both sides.

  2. precal
    • 2 years ago
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    |dw:1359074224200:dw|do just like tyteen4a03 suggested

  3. Hally
    • 2 years ago
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    a=64?

  4. Hally
    • 2 years ago
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    so, is it b or c??

  5. Hally
    • 2 years ago
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    i say c. am i right??

  6. tyteen4a03
    • 2 years ago
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    @Hally The answer is B. Whenever you are raising a number to an even number, the negative sign disappears. (If you need proof just ask.)

  7. Hally
    • 2 years ago
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    i know that part thanks! :)

  8. precal
    • 2 years ago
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    |dw:1359074648834:dw|

  9. precal
    • 2 years ago
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    |dw:1359074661681:dw|question is, is this true?

  10. Hally
    • 2 years ago
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    no. sqrt 64 = 8 and 8 is not equal to -8

  11. precal
    • 2 years ago
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    |dw:1359074893672:dw|

  12. precal
    • 2 years ago
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    then that means that the solution is extraneous

  13. Hally
    • 2 years ago
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    oh. so the answer is "64 is a solution of the original equation. –64 is an extraneous solution" .... right?

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