babyjay
Can someone help me I have the problem solved but do not know how to determine the restriction variables.
x2/x+3 plus 10x/x^29



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precal
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restriction is the value that would make the denominator equal 0

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one of the math commandments is "thou shall not divide by zero"

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dw:1359076743638:dw

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do you know see what number x can not be

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dw:1359076865546:dw

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do you see what x can not be?

babyjay
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are you talking about 3

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yes but also, another number

babyjay
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3 and 3

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dw:1359077321883:dw

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bingo, you got it

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dw:1359077374821:dw

babyjay
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do you work the problem out further like (x^25x+6)+10x/(x+3)(x3)

precal
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yes, keep going

babyjay
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then x^2+5x+6/(x+3)(x3)
(x+3)(x+2)/(x+3)(x3)
answer x=2/x3;x=/3,3

precal
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yes perfect, gotta go........