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Can someone help me I have the problem solved but do not know how to determine the restriction variables. x-2/x+3 plus 10x/x^2-9

Mathematics
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restriction is the value that would make the denominator equal 0
one of the math commandments is "thou shall not divide by zero"
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Other answers:

do you know see what number x can not be
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do you see what x can not be?
are you talking about 3
yes but also, another number
3 and -3
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bingo, you got it
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do you work the problem out further like (x^2-5x+6)+10x/(x+3)(x-3)
yes, keep going
then x^2+5x+6/(x+3)(x-3) (x+3)(x+2)/(x+3)(x-3) answer x=2/x-3;x=/-3,3
yes perfect, gotta go........

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