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babyjay
 3 years ago
Can someone help me I have the problem solved but do not know how to determine the restriction variables.
x2/x+3 plus 10x/x^29
babyjay
 3 years ago
Can someone help me I have the problem solved but do not know how to determine the restriction variables. x2/x+3 plus 10x/x^29

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precal
 3 years ago
Best ResponseYou've already chosen the best response.1restriction is the value that would make the denominator equal 0

precal
 3 years ago
Best ResponseYou've already chosen the best response.1one of the math commandments is "thou shall not divide by zero"

precal
 3 years ago
Best ResponseYou've already chosen the best response.1do you know see what number x can not be

precal
 3 years ago
Best ResponseYou've already chosen the best response.1do you see what x can not be?

babyjay
 3 years ago
Best ResponseYou've already chosen the best response.0are you talking about 3

precal
 3 years ago
Best ResponseYou've already chosen the best response.1yes but also, another number

babyjay
 3 years ago
Best ResponseYou've already chosen the best response.0do you work the problem out further like (x^25x+6)+10x/(x+3)(x3)

babyjay
 3 years ago
Best ResponseYou've already chosen the best response.0then x^2+5x+6/(x+3)(x3) (x+3)(x+2)/(x+3)(x3) answer x=2/x3;x=/3,3

precal
 3 years ago
Best ResponseYou've already chosen the best response.1yes perfect, gotta go........
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