anonymous
  • anonymous
Can someone help me I have the problem solved but do not know how to determine the restriction variables. x-2/x+3 plus 10x/x^2-9
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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precal
  • precal
restriction is the value that would make the denominator equal 0
precal
  • precal
one of the math commandments is "thou shall not divide by zero"
precal
  • precal
|dw:1359076743638:dw|

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precal
  • precal
do you know see what number x can not be
precal
  • precal
|dw:1359076865546:dw|
precal
  • precal
do you see what x can not be?
anonymous
  • anonymous
are you talking about 3
precal
  • precal
yes but also, another number
anonymous
  • anonymous
3 and -3
precal
  • precal
|dw:1359077321883:dw|
precal
  • precal
bingo, you got it
precal
  • precal
|dw:1359077374821:dw|
anonymous
  • anonymous
do you work the problem out further like (x^2-5x+6)+10x/(x+3)(x-3)
precal
  • precal
yes, keep going
anonymous
  • anonymous
then x^2+5x+6/(x+3)(x-3) (x+3)(x+2)/(x+3)(x-3) answer x=2/x-3;x=/-3,3
precal
  • precal
yes perfect, gotta go........

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