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A company wants to transmit data over the telephone lines. All their data is transmitted as fourdigit integers. write a program that will encrypt their data so that it may be transmitted more securely. Your program should read a four digit number and encrypt as follows: replace each digit by the remainder after the sum of that digit plus 7 is divided by 10. Then swap the first digit with the third, and swap the second digit with the fourth. Then print the encypted integer. Write a seperate program that inputs an encrypted fourdigit integer and decrypts it to form the original number
 one year ago
 one year ago
A company wants to transmit data over the telephone lines. All their data is transmitted as fourdigit integers. write a program that will encrypt their data so that it may be transmitted more securely. Your program should read a four digit number and encrypt as follows: replace each digit by the remainder after the sum of that digit plus 7 is divided by 10. Then swap the first digit with the third, and swap the second digit with the fourth. Then print the encypted integer. Write a seperate program that inputs an encrypted fourdigit integer and decrypts it to form the original number
 one year ago
 one year ago

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bunyonbBest ResponseYou've already chosen the best response.0
You need to use While Loop too
 one year ago

bunyonbBest ResponseYou've already chosen the best response.0
Here is what i have so far... #include <iostream> using namespace std; int main(){ int num=0;int encrypted_num=0;int digit[3]; cout<< " Input: " cin>>num; if (num> 1000  num<1000){ cout<< "
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
you might want to use an array to keep the numbers. and......is the while loop really required?
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
#include <iostream> #include <math.h> using namespace std; int main() { int num[4]; int a,b,c; cin >>a; if (a<10000) { if(a>1000) { for(int i=0; i<4;i++){ b=pow(10, i+1); num[i]=a%b; a=a%b; if (i>0){ c=pow(10,i); cout<<num[i]; num[i]/=c; cout<<"h"; cout<<num[i]; } } } } else { cin.clear(); while (cin.get() != '\n') ; cout<<"hello"; cin>>a; } for(int i=0;i<4;i++){ num[i]+=7; num[i]=num[i]%10; } cout<<num[0]; cout<<num[1]; cout<<num[2]; cout<<num[3]; }
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
sample code for using a array to keep the numbers for easy reference. to interchange the values, keep the element in another symbol before assigning it away.
 one year ago

bunyonbBest ResponseYou've already chosen the best response.0
Too late man. I failed
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
sigh. i guess that's no help then. LOL good luck next time
 one year ago
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