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 one year ago
A company wants to transmit data over the telephone lines. All their data is transmitted as fourdigit integers. write a program that will encrypt their data so that it may be transmitted more securely. Your program should read a four digit number and encrypt as follows: replace each digit by the remainder after the sum of that digit plus 7 is divided by 10. Then swap the first digit with the third, and swap the second digit with the fourth. Then print the encypted integer. Write a seperate program that inputs an encrypted fourdigit integer and decrypts it to form the original number
 one year ago
A company wants to transmit data over the telephone lines. All their data is transmitted as fourdigit integers. write a program that will encrypt their data so that it may be transmitted more securely. Your program should read a four digit number and encrypt as follows: replace each digit by the remainder after the sum of that digit plus 7 is divided by 10. Then swap the first digit with the third, and swap the second digit with the fourth. Then print the encypted integer. Write a seperate program that inputs an encrypted fourdigit integer and decrypts it to form the original number

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bunyonb
 one year ago
Best ResponseYou've already chosen the best response.0You need to use While Loop too

bunyonb
 one year ago
Best ResponseYou've already chosen the best response.0Here is what i have so far... #include <iostream> using namespace std; int main(){ int num=0;int encrypted_num=0;int digit[3]; cout<< " Input: " cin>>num; if (num> 1000  num<1000){ cout<< "

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.0you might want to use an array to keep the numbers. and......is the while loop really required?

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.0#include <iostream> #include <math.h> using namespace std; int main() { int num[4]; int a,b,c; cin >>a; if (a<10000) { if(a>1000) { for(int i=0; i<4;i++){ b=pow(10, i+1); num[i]=a%b; a=a%b; if (i>0){ c=pow(10,i); cout<<num[i]; num[i]/=c; cout<<"h"; cout<<num[i]; } } } } else { cin.clear(); while (cin.get() != '\n') ; cout<<"hello"; cin>>a; } for(int i=0;i<4;i++){ num[i]+=7; num[i]=num[i]%10; } cout<<num[0]; cout<<num[1]; cout<<num[2]; cout<<num[3]; }

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.0sample code for using a array to keep the numbers for easy reference. to interchange the values, keep the element in another symbol before assigning it away.

bunyonb
 one year ago
Best ResponseYou've already chosen the best response.0Too late man. I failed

Shadowys
 one year ago
Best ResponseYou've already chosen the best response.0sigh. i guess that's no help then. LOL good luck next time
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