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Try applying the quadratic equation to this one.

\[x = \frac{ -b \pm \sqrt{b^{2} - 4ac} }{ 2a }\]

@BubbaMurphy Do you have a different way to do this problem???

LogicApple's way is definitely the way to do it.

in this case, a=1

Is that really how yo would solve it

would A, B, and C = 1

Based on the equation you supplied, a = 1, b = b, and c = c.

They are coefficients of whatever quadratic you are talking about. Did you have a quadratic in mind?

what you mean

Yea I know that

Oh, ok... so what is your question?

We have to solve x^2 + bx + c = 0 for bonus and I have no idea what to do

We didn't learn that equation you gave me

What about completing the square ?

so is that the answer

I have to show my work, so how would I show it

b^2/4

|dw:1359082578453:dw|

(b/2)^2 = b^2/4

After (x + b/2)^2 = b^2/4 - c. Find the square root of both.

Yes

I got x + b/2 = b/4 - c. Is that correct?

no the square root of both sides gives:
x + b/2 = ± sqrt(b^2/4 - c)

what then

All the steps are in the picture attached.

I am sorry the last step in attachment is the answer

Oh ok did you get it figured out ?

so x = +/- sqrt b^2 - 4c /2 is the answer

|dw:1359083804186:dw|
yes

Will you forgive me @LogicalApple ?

What for? It's a learning experience

I probably annoyed you a lot