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LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Try applying the quadratic equation to this one.
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
@LogicalApple
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
\[x = \frac{ b \pm \sqrt{b^{2}  4ac} }{ 2a }\]
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
@BubbaMurphy Do you have a different way to do this problem???
 one year ago

BubbaMurphy Group TitleBest ResponseYou've already chosen the best response.0
LogicApple's way is definitely the way to do it.
 one year ago

BubbaMurphy Group TitleBest ResponseYou've already chosen the best response.0
in this case, a=1
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
Is that really how yo would solve it
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
would A, B, and C = 1
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Based on the equation you supplied, a = 1, b = b, and c = c.
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
They are coefficients of whatever quadratic you are talking about. Did you have a quadratic in mind?
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
what you mean
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
\[6x^{2}  9x + 12 = 0\] \[5x^{2} + x  10 = 0\] \[x^2 + x  1 = 0\] These are some examples of quadratics, all set equal to 0.
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
Yea I know that
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Oh, ok... so what is your question?
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
We have to solve x^2 + bx + c = 0 for bonus and I have no idea what to do
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
I suggested using the quadratic equation. The only difference between x^2 + bx + c = 0 and the quadratics that I mentioned is that the coefficients in your equation are only known by their variable letter. But that is ok, you can still apply the quadratic formula to them. The solutions to x^2 + bx + c = 0 is: \[\frac{ b \pm \sqrt{b^{2}  4c} }{ 2 }\] This is the same thing I wrote before, except I let a = 1 because the coefficient of x^2 in your equation is 1.
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
We didn't learn that equation you gave me
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
What about completing the square ?
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
so is that the answer
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Yes, but you would arrive at the same answer if you complete the square. Both techniques are valid for solving quadratic equations.
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
I have to show my work, so how would I show it
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Well if you're using the quadratic equation you could say "applying the quadratic equation". But if you wanted to complete the square then: dw:1359081924838:dw
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.0
I think you can use sum and product of roots: \[\alpha +\beta= \frac{ b }{ a }\] \[\alpha \beta=\frac{ c }{ a }\]
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
dw:1359082578453:dw
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
(b/2)^2 = b^2/4
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
After (x + b/2)^2 = b^2/4  c. Find the square root of both.
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
I got x + b/2 = b/4  c. Is that correct?
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
no the square root of both sides gives: x + b/2 = ± sqrt(b^2/4  c)
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
what then
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
All the steps are in the picture attached.
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
I am sorry the last step in attachment is the answer
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Oh ok did you get it figured out ?
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
so x = +/ sqrt b^2  4c /2 is the answer
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
dw:1359083804186:dw yes
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
Will you forgive me @LogicalApple ?
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
What for? It's a learning experience
 one year ago

Firejay5 Group TitleBest ResponseYou've already chosen the best response.1
I probably annoyed you a lot
 one year ago
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