Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Firejay5

  • one year ago

Solve and show and explain work x^2 + bx + c = 0

  • This Question is Closed
  1. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Try applying the quadratic equation to this one.

  2. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @LogicalApple

  3. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[x = \frac{ -b \pm \sqrt{b^{2} - 4ac} }{ 2a }\]

  4. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @BubbaMurphy Do you have a different way to do this problem???

  5. BubbaMurphy
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    LogicApple's way is definitely the way to do it.

  6. BubbaMurphy
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    in this case, a=1

  7. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Is that really how yo would solve it

  8. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    would A, B, and C = 1

  9. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Based on the equation you supplied, a = 1, b = b, and c = c.

  10. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    They are coefficients of whatever quadratic you are talking about. Did you have a quadratic in mind?

  11. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    what you mean

  12. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[6x^{2} - 9x + 12 = 0\] \[-5x^{2} + x - 10 = 0\] \[x^2 + x - 1 = 0\] These are some examples of quadratics, all set equal to 0.

  13. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yea I know that

  14. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh, ok... so what is your question?

  15. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    We have to solve x^2 + bx + c = 0 for bonus and I have no idea what to do

  16. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I suggested using the quadratic equation. The only difference between x^2 + bx + c = 0 and the quadratics that I mentioned is that the coefficients in your equation are only known by their variable letter. But that is ok, you can still apply the quadratic formula to them. The solutions to x^2 + bx + c = 0 is: \[\frac{ -b \pm \sqrt{b^{2} - 4c} }{ 2 }\] This is the same thing I wrote before, except I let a = 1 because the coefficient of x^2 in your equation is 1.

  17. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    We didn't learn that equation you gave me

  18. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    What about completing the square ?

  19. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so is that the answer

  20. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes, but you would arrive at the same answer if you complete the square. Both techniques are valid for solving quadratic equations.

  21. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I have to show my work, so how would I show it

  22. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Well if you're using the quadratic equation you could say "applying the quadratic equation". But if you wanted to complete the square then: |dw:1359081924838:dw|

  23. Azteck
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think you can use sum and product of roots: \[\alpha +\beta= \frac{ -b }{ a }\] \[\alpha \beta=\frac{ c }{ a }\]

  24. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    b^2/4

  25. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    1 Attachment
  26. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1359082578453:dw|

  27. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    (b/2)^2 = b^2/4

  28. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    After (x + b/2)^2 = b^2/4 - c. Find the square root of both.

  29. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes

  30. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I got x + b/2 = b/4 - c. Is that correct?

  31. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    no the square root of both sides gives: x + b/2 = ± sqrt(b^2/4 - c)

  32. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    what then

  33. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    All the steps are in the picture attached.

    1 Attachment
  34. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I am sorry the last step in attachment is the answer

  35. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Oh ok did you get it figured out ?

  36. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so x = +/- sqrt b^2 - 4c /2 is the answer

  37. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1359083804186:dw| yes

  38. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Will you forgive me @LogicalApple ?

  39. LogicalApple
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    What for? It's a learning experience

  40. Firejay5
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I probably annoyed you a lot

  41. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.