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Use the maxmin inequality to show that if f is integrable then f(x) ≤ 0 on [a,b] > ∫ (from a to be) f(x) d(X) ≥ 0
 one year ago
 one year ago
Use the maxmin inequality to show that if f is integrable then f(x) ≤ 0 on [a,b] > ∫ (from a to be) f(x) d(X) ≥ 0
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.0
of \(f(x)\) is never positive, then neither is the integral
 one year ago

swin2013Best ResponseYou've already chosen the best response.0
are you saying there is no way of showing it? or the question does not have a definite answer?
 one year ago
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