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swin2013

  • 3 years ago

Use the max-min inequality to show that if f is integrable then f(x) ≤ 0 on [a,b] -> ∫ (from a to be) f(x) d(X) ≥ 0

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  1. anonymous
    • 3 years ago
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    seems unlikely

  2. anonymous
    • 3 years ago
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    of \(f(x)\) is never positive, then neither is the integral

  3. swin2013
    • 3 years ago
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    are you saying there is no way of showing it? or the question does not have a definite answer?

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