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anonymous
 3 years ago
Use the maxmin inequality to show that if f is integrable then f(x) ≤ 0 on [a,b] > ∫ (from a to be) f(x) d(X) ≥ 0
anonymous
 3 years ago
Use the maxmin inequality to show that if f is integrable then f(x) ≤ 0 on [a,b] > ∫ (from a to be) f(x) d(X) ≥ 0

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0of \(f(x)\) is never positive, then neither is the integral

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0are you saying there is no way of showing it? or the question does not have a definite answer?
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