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 one year ago
Use the maxmin inequality to show that if f is integrable then f(x) ≤ 0 on [a,b] > ∫ (from a to be) f(x) d(X) ≥ 0
 one year ago
Use the maxmin inequality to show that if f is integrable then f(x) ≤ 0 on [a,b] > ∫ (from a to be) f(x) d(X) ≥ 0

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satellite73
 one year ago
Best ResponseYou've already chosen the best response.0of \(f(x)\) is never positive, then neither is the integral

swin2013
 one year ago
Best ResponseYou've already chosen the best response.0are you saying there is no way of showing it? or the question does not have a definite answer?
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