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mathslover Group Title

Convert into polar form : (-1/2) + i ( \(\frac{-\sqrt{3}}{2}\) )

  • one year ago
  • one year ago

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  1. mathslover Group Title
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    (-1/2) + i ( \(-\frac{\sqrt{3}}{2}\) )

    • one year ago
  2. mathslover Group Title
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    I got : cos ( 4 pi/3 ) + sin ( 4 pi/3)

    • one year ago
  3. mathslover Group Title
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    But the book says : cos ( - 2pi/3 ) + i sin ( - 2pi/3). Which is also right...

    • one year ago
  4. Azteck Group Title
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    isin

    • one year ago
  5. Azteck Group Title
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    You're wrong.

    • one year ago
  6. mathslover Group Title
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    Sorry typing mistake I meant i sin 4pi/3

    • one year ago
  7. mathslover Group Title
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    ^ cos ( 4 pi/3 ) + i sin(4pi/3)

    • one year ago
  8. Azteck Group Title
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    Find the absolute value of this: \[\left| -\frac{ 1 }{ 2 } -\frac{ i \sqrt{3} }{ 2 }\right|\]

    • one year ago
  9. mathslover Group Title
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    So which should I prefer more ? -2pi/3 or 4 pi/3

    • one year ago
  10. Azteck Group Title
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    So \[=\sqrt{(-\frac{ 1 }{ 2 })^2+(-\frac{ \sqrt{3} }{ 2 })^2}\]

    • one year ago
  11. Azteck Group Title
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    So r=1

    • one year ago
  12. Azteck Group Title
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    Now draw it.

    • one year ago
  13. Azteck Group Title
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    Drawing it gives you a way better picture of what the angle is.

    • one year ago
  14. mathslover Group Title
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    \[\large{\sqrt{ (\frac{-1}{2} )^2 + ( \frac {- \sqrt{3}}{2})^2}}\] right so it is : \(\1\)

    • one year ago
  15. Azteck Group Title
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    |dw:1359153193735:dw|

    • one year ago
  16. Azteck Group Title
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    You took the other angle

    • one year ago
  17. Azteck Group Title
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    You go backwards meaning it will be negative.

    • one year ago
  18. mathslover Group Title
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    By the diagram I think that the angle theta will surely lie in the III quadrant i.e. 4 pi /3

    • one year ago
  19. mathslover Group Title
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    Ok got it thanks.

    • one year ago
  20. Azteck Group Title
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    If it's in the third of fourth quadrant go backwards.

    • one year ago
  21. Azteck Group Title
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    third or fourth*

    • one year ago
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