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Convert into polar form :
(1/2) + i ( \(\frac{\sqrt{3}}{2}\) )
 one year ago
 one year ago
Convert into polar form : (1/2) + i ( \(\frac{\sqrt{3}}{2}\) )
 one year ago
 one year ago

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mathsloverBest ResponseYou've already chosen the best response.0
(1/2) + i ( \(\frac{\sqrt{3}}{2}\) )
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
I got : cos ( 4 pi/3 ) + sin ( 4 pi/3)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
But the book says : cos (  2pi/3 ) + i sin (  2pi/3). Which is also right...
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
Sorry typing mistake I meant i sin 4pi/3
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
^ cos ( 4 pi/3 ) + i sin(4pi/3)
 one year ago

AzteckBest ResponseYou've already chosen the best response.1
Find the absolute value of this: \[\left \frac{ 1 }{ 2 } \frac{ i \sqrt{3} }{ 2 }\right\]
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
So which should I prefer more ? 2pi/3 or 4 pi/3
 one year ago

AzteckBest ResponseYou've already chosen the best response.1
So \[=\sqrt{(\frac{ 1 }{ 2 })^2+(\frac{ \sqrt{3} }{ 2 })^2}\]
 one year ago

AzteckBest ResponseYou've already chosen the best response.1
Drawing it gives you a way better picture of what the angle is.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
\[\large{\sqrt{ (\frac{1}{2} )^2 + ( \frac { \sqrt{3}}{2})^2}}\] right so it is : \(\1\)
 one year ago

AzteckBest ResponseYou've already chosen the best response.1
You took the other angle
 one year ago

AzteckBest ResponseYou've already chosen the best response.1
You go backwards meaning it will be negative.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.0
By the diagram I think that the angle theta will surely lie in the III quadrant i.e. 4 pi /3
 one year ago

AzteckBest ResponseYou've already chosen the best response.1
If it's in the third of fourth quadrant go backwards.
 one year ago
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