mathslover
  • mathslover
Convert into polar form : (-1/2) + i ( \(\frac{-\sqrt{3}}{2}\) )
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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mathslover
  • mathslover
(-1/2) + i ( \(-\frac{\sqrt{3}}{2}\) )
mathslover
  • mathslover
I got : cos ( 4 pi/3 ) + sin ( 4 pi/3)
mathslover
  • mathslover
But the book says : cos ( - 2pi/3 ) + i sin ( - 2pi/3). Which is also right...

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anonymous
  • anonymous
isin
anonymous
  • anonymous
You're wrong.
mathslover
  • mathslover
Sorry typing mistake I meant i sin 4pi/3
mathslover
  • mathslover
^ cos ( 4 pi/3 ) + i sin(4pi/3)
anonymous
  • anonymous
Find the absolute value of this: \[\left| -\frac{ 1 }{ 2 } -\frac{ i \sqrt{3} }{ 2 }\right|\]
mathslover
  • mathslover
So which should I prefer more ? -2pi/3 or 4 pi/3
anonymous
  • anonymous
So \[=\sqrt{(-\frac{ 1 }{ 2 })^2+(-\frac{ \sqrt{3} }{ 2 })^2}\]
anonymous
  • anonymous
So r=1
anonymous
  • anonymous
Now draw it.
anonymous
  • anonymous
Drawing it gives you a way better picture of what the angle is.
mathslover
  • mathslover
\[\large{\sqrt{ (\frac{-1}{2} )^2 + ( \frac {- \sqrt{3}}{2})^2}}\] right so it is : \(\1\)
anonymous
  • anonymous
|dw:1359153193735:dw|
anonymous
  • anonymous
You took the other angle
anonymous
  • anonymous
You go backwards meaning it will be negative.
mathslover
  • mathslover
By the diagram I think that the angle theta will surely lie in the III quadrant i.e. 4 pi /3
mathslover
  • mathslover
Ok got it thanks.
anonymous
  • anonymous
If it's in the third of fourth quadrant go backwards.
anonymous
  • anonymous
third or fourth*

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