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burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1359089106003:dw
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
i can substitute 2^2 for u for all terms but the last .. idk what to do !
 one year ago

JayDS Group TitleBest ResponseYou've already chosen the best response.0
hint: first put them all to the lowest base of 2.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ 1 }{ \sqrt{2} }=2^{\frac{ 1 }{ 2 }}\]
 one year ago

JayDS Group TitleBest ResponseYou've already chosen the best response.0
yep, @Azteck has shown u the harder one, try to do the rest yourself. Post it on here so I/others can help u check it.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
@JayDS He only wanted to know the last one. Read what he said above.
 one year ago

JayDS Group TitleBest ResponseYou've already chosen the best response.0
oh kk sorry, I didn't quite understand how he phrased it.
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
\[4^2(2^{x  3}) = 16^{x2}\] Is that the whole thing @burhan101 ?
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Because if it is, it works out quite nicely
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
no @Hero you are missing the last term
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1359091740887:dw
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
\[4^2 \dot\ 2^{x  3} = \frac{16^{x  2}}{\sqrt{2}} \\4^2\dot\ 2^x2^{3} = \frac{16^x16^{2}}{\sqrt{2}} \\\frac{4^2 \dot\ 2^x}{2^3} = \frac{16^x}{16^2 \sqrt{2}} \\\frac{4^2 \dot\ 16^2 \sqrt{2}}{2^3}= \frac{16^x}{2^x} \\512\sqrt{2} = \left(\frac{16}{2}\right)^x \\512\sqrt{2} = \left(8\right)^x \] You should be able to finish it from there by taking logs of both sides and simplifying
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
thank you but this is not the method my teacher wants, she wants us to substitute
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Substitute what?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
like a variable like let's say use q to represent something
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Why would she want you to do that? It simplifies quite nicely without it.
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
I wish i knew . something about knowing a wide variety of methods
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
If you take logs of both sides you get: \[\ln(512 \dot\ \sqrt{2}) = x \ln(8) \\\frac{\ln(512) + \ln(\sqrt{2})}{\ln(8)} = x \\\frac{\ln(2^9) + \ln(2^{1/2})}{\ln(2^3)} = x \\\frac{9\ln(2) + .5\ln(2)}{3\ln(2)} = x \\\frac{9.5 \ln(2)}{3 \ln(2)} = x \\\frac{9.5}{3} = x \]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
\[(2^2)^2(2^{2x3})=(16^{x2})(\frac{ 1 }{ \sqrt{2} })\] \[(2^4)(2^{2x3})=(2^{4x8})(2^{\frac{ 1 }{ 2 }})\] \[2^{2x3+4}=2^{4x8\frac{ 1 }{ 2 }}\] \[2^{2x+1}=2^{4x\frac{ 17 }{ 2 }}\] \[2x+1=4x\frac{ 17 }{ 2 }\] \[4x+2=8x17\] Solve for x.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
@Hero you copied the wrong indice.
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
Good job bro.
 one year ago
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