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burhan101
 3 years ago
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burhan101
 3 years ago
Solve

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burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359089106003:dw

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0i can substitute 2^2 for u for all terms but the last .. idk what to do !

JayDS
 3 years ago
Best ResponseYou've already chosen the best response.0hint: first put them all to the lowest base of 2.

Azteck
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 1 }{ \sqrt{2} }=2^{\frac{ 1 }{ 2 }}\]

JayDS
 3 years ago
Best ResponseYou've already chosen the best response.0yep, @Azteck has shown u the harder one, try to do the rest yourself. Post it on here so I/others can help u check it.

Azteck
 3 years ago
Best ResponseYou've already chosen the best response.1@JayDS He only wanted to know the last one. Read what he said above.

JayDS
 3 years ago
Best ResponseYou've already chosen the best response.0oh kk sorry, I didn't quite understand how he phrased it.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1\[4^2(2^{x  3}) = 16^{x2}\] Is that the whole thing @burhan101 ?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Because if it is, it works out quite nicely

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0no @Hero you are missing the last term

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359091740887:dw

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1\[4^2 \dot\ 2^{x  3} = \frac{16^{x  2}}{\sqrt{2}} \\4^2\dot\ 2^x2^{3} = \frac{16^x16^{2}}{\sqrt{2}} \\\frac{4^2 \dot\ 2^x}{2^3} = \frac{16^x}{16^2 \sqrt{2}} \\\frac{4^2 \dot\ 16^2 \sqrt{2}}{2^3}= \frac{16^x}{2^x} \\512\sqrt{2} = \left(\frac{16}{2}\right)^x \\512\sqrt{2} = \left(8\right)^x \] You should be able to finish it from there by taking logs of both sides and simplifying

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0thank you but this is not the method my teacher wants, she wants us to substitute

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0like a variable like let's say use q to represent something

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Why would she want you to do that? It simplifies quite nicely without it.

burhan101
 3 years ago
Best ResponseYou've already chosen the best response.0I wish i knew . something about knowing a wide variety of methods

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1If you take logs of both sides you get: \[\ln(512 \dot\ \sqrt{2}) = x \ln(8) \\\frac{\ln(512) + \ln(\sqrt{2})}{\ln(8)} = x \\\frac{\ln(2^9) + \ln(2^{1/2})}{\ln(2^3)} = x \\\frac{9\ln(2) + .5\ln(2)}{3\ln(2)} = x \\\frac{9.5 \ln(2)}{3 \ln(2)} = x \\\frac{9.5}{3} = x \]

Azteck
 3 years ago
Best ResponseYou've already chosen the best response.1\[(2^2)^2(2^{2x3})=(16^{x2})(\frac{ 1 }{ \sqrt{2} })\] \[(2^4)(2^{2x3})=(2^{4x8})(2^{\frac{ 1 }{ 2 }})\] \[2^{2x3+4}=2^{4x8\frac{ 1 }{ 2 }}\] \[2^{2x+1}=2^{4x\frac{ 17 }{ 2 }}\] \[2x+1=4x\frac{ 17 }{ 2 }\] \[4x+2=8x17\] Solve for x.

Azteck
 3 years ago
Best ResponseYou've already chosen the best response.1@Hero you copied the wrong indice.
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