A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Solve
anonymous
 3 years ago
Solve

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359089106003:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i can substitute 2^2 for u for all terms but the last .. idk what to do !

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hint: first put them all to the lowest base of 2.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ \sqrt{2} }=2^{\frac{ 1 }{ 2 }}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yep, @Azteck has shown u the harder one, try to do the rest yourself. Post it on here so I/others can help u check it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@JayDS He only wanted to know the last one. Read what he said above.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh kk sorry, I didn't quite understand how he phrased it.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1\[4^2(2^{x  3}) = 16^{x2}\] Is that the whole thing @burhan101 ?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Because if it is, it works out quite nicely

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no @Hero you are missing the last term

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359091740887:dw

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1\[4^2 \dot\ 2^{x  3} = \frac{16^{x  2}}{\sqrt{2}} \\4^2\dot\ 2^x2^{3} = \frac{16^x16^{2}}{\sqrt{2}} \\\frac{4^2 \dot\ 2^x}{2^3} = \frac{16^x}{16^2 \sqrt{2}} \\\frac{4^2 \dot\ 16^2 \sqrt{2}}{2^3}= \frac{16^x}{2^x} \\512\sqrt{2} = \left(\frac{16}{2}\right)^x \\512\sqrt{2} = \left(8\right)^x \] You should be able to finish it from there by taking logs of both sides and simplifying

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you but this is not the method my teacher wants, she wants us to substitute

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0like a variable like let's say use q to represent something

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1Why would she want you to do that? It simplifies quite nicely without it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I wish i knew . something about knowing a wide variety of methods

Hero
 3 years ago
Best ResponseYou've already chosen the best response.1If you take logs of both sides you get: \[\ln(512 \dot\ \sqrt{2}) = x \ln(8) \\\frac{\ln(512) + \ln(\sqrt{2})}{\ln(8)} = x \\\frac{\ln(2^9) + \ln(2^{1/2})}{\ln(2^3)} = x \\\frac{9\ln(2) + .5\ln(2)}{3\ln(2)} = x \\\frac{9.5 \ln(2)}{3 \ln(2)} = x \\\frac{9.5}{3} = x \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[(2^2)^2(2^{2x3})=(16^{x2})(\frac{ 1 }{ \sqrt{2} })\] \[(2^4)(2^{2x3})=(2^{4x8})(2^{\frac{ 1 }{ 2 }})\] \[2^{2x3+4}=2^{4x8\frac{ 1 }{ 2 }}\] \[2^{2x+1}=2^{4x\frac{ 17 }{ 2 }}\] \[2x+1=4x\frac{ 17 }{ 2 }\] \[4x+2=8x17\] Solve for x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Hero you copied the wrong indice.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.