Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
A soccer ball is kicked in space, where we assume there is no friction or other forces acting on the ball, at 13 m/s. How much force is needed to keep the ball moving?
 one year ago
 one year ago
A soccer ball is kicked in space, where we assume there is no friction or other forces acting on the ball, at 13 m/s. How much force is needed to keep the ball moving?
 one year ago
 one year ago

This Question is Open

Outkast3r09Best ResponseYou've already chosen the best response.0
\[S=\frac{1}{2}at^2+vt+s_0\] \[S=\frac{1}{2}at^2+vt\] \[V=at+V_0\] assuming the ball was sitting in space at rest \[V=at=13\] \[\frac{13}{a}=t\]
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
None. since there is no other forces impeding its movement, and since it is moving with uniform velocity, then it will, by Newton's first law, continue to move.
 one year ago

Outkast3r09Best ResponseYou've already chosen the best response.0
I thought the question asked what was the force upon the ball .
 one year ago

ShadowysBest ResponseYou've already chosen the best response.1
yes. the question asks what is the force on the ball that keeps it moving.
 one year ago

TimSmitBest ResponseYou've already chosen the best response.0
In the case of the force required to get the ball to 13 m/s, it also depends on how long you exert the force and the mass of the ball. If you apply 10000N but only for a microsecond, you won't gain much velocity. The relation between force and acceleration is \[F = m*a = m * \frac{ \Delta v }{ \Delta t }\] Then, to gain a speed of 13 m/s, the relation is: \[13 = \frac{ F * \Delta t }{ m }\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.