A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
A soccer ball is kicked in space, where we assume there is no friction or other forces acting on the ball, at 13 m/s. How much force is needed to keep the ball moving?
 2 years ago
A soccer ball is kicked in space, where we assume there is no friction or other forces acting on the ball, at 13 m/s. How much force is needed to keep the ball moving?

This Question is Open

Outkast3r09
 2 years ago
Best ResponseYou've already chosen the best response.0\[S=\frac{1}{2}at^2+vt+s_0\] \[S=\frac{1}{2}at^2+vt\] \[V=at+V_0\] assuming the ball was sitting in space at rest \[V=at=13\] \[\frac{13}{a}=t\]

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.1None. since there is no other forces impeding its movement, and since it is moving with uniform velocity, then it will, by Newton's first law, continue to move.

Outkast3r09
 2 years ago
Best ResponseYou've already chosen the best response.0I thought the question asked what was the force upon the ball .

Shadowys
 2 years ago
Best ResponseYou've already chosen the best response.1yes. the question asks what is the force on the ball that keeps it moving.

TimSmit
 one year ago
Best ResponseYou've already chosen the best response.0In the case of the force required to get the ball to 13 m/s, it also depends on how long you exert the force and the mass of the ball. If you apply 10000N but only for a microsecond, you won't gain much velocity. The relation between force and acceleration is \[F = m*a = m * \frac{ \Delta v }{ \Delta t }\] Then, to gain a speed of 13 m/s, the relation is: \[13 = \frac{ F * \Delta t }{ m }\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.