Here's the question you clicked on:
john18sanders
solve by completing the square: 4x^2-7x=3
do u know the method of completing the square first............?
firstly make the coefficient of first term ie,x^2 unity
if all us fails.. u can even use the quadractic formula
NO, the question says to complete the square. @Goten77 if you're good at maths then you should know to never make a rookie mistake of not obeying to the question.
\[4x^2-7x=3\] Divide both sides by 4! \[x^2-\frac{7}{4}x=\frac{3}{4}\] Use this property of completing the square. \[x^2-bx=c\] \[(x-\frac{b}{2})^2=c+(\frac{b}{2})^2\] SO.... \[(x-\frac{ 7 }{ 8 })^2=\frac{ 3 }{ 4 }+\frac{ 49 }{ 64 }\] \[(x-\frac{ 7 }{ 8 })^2=\frac{ 97 }{ 64 }\] Square root both sides while BEING CAUTIOUS that there must be a negative value as well as a positive. \[x-\frac{ 7 }{ 8 }=\frac{ \pm \sqrt{97} }{ 8 }\] \[x=\frac{ \pm \sqrt{97} }{ 8 }+\frac{ 7 }{ 8 }\] \[x=\frac{ 7\pm \sqrt{97} }{ 8 }\]