Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

nitz Group TitleBest ResponseYou've already chosen the best response.1
do u know the method of completing the square first............?
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.1
firstly make the coefficient of first term ie,x^2 unity
 one year ago

Goten77 Group TitleBest ResponseYou've already chosen the best response.0
dw:1359101474085:dw
 one year ago

Goten77 Group TitleBest ResponseYou've already chosen the best response.0
if all us fails.. u can even use the quadractic formula
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.0
NO, the question says to complete the square. @Goten77 if you're good at maths then you should know to never make a rookie mistake of not obeying to the question.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.0
\[4x^27x=3\] Divide both sides by 4! \[x^2\frac{7}{4}x=\frac{3}{4}\] Use this property of completing the square. \[x^2bx=c\] \[(x\frac{b}{2})^2=c+(\frac{b}{2})^2\] SO.... \[(x\frac{ 7 }{ 8 })^2=\frac{ 3 }{ 4 }+\frac{ 49 }{ 64 }\] \[(x\frac{ 7 }{ 8 })^2=\frac{ 97 }{ 64 }\] Square root both sides while BEING CAUTIOUS that there must be a negative value as well as a positive. \[x\frac{ 7 }{ 8 }=\frac{ \pm \sqrt{97} }{ 8 }\] \[x=\frac{ \pm \sqrt{97} }{ 8 }+\frac{ 7 }{ 8 }\] \[x=\frac{ 7\pm \sqrt{97} }{ 8 }\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.