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SmokeysTheName

Simplify the rational expression. State any restrictions on the variable

  • one year ago
  • one year ago

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  1. SmokeysTheName
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    • one year ago
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  2. SmokeysTheName
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    please help and explain.?

    • one year ago
  3. UnkleRhaukus
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    can you factorise the numerator and the denominator ?

    • one year ago
  4. SmokeysTheName
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    yeah gimme a sec lemme do that real quick

    • one year ago
  5. SmokeysTheName
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    the numerator is (t+6)(t-4) im not sure how to factor the denominator.. i always forget.. i think its (t+6)(t-6) -- am i right?

    • one year ago
  6. UnkleRhaukus
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    good work, that is right . now you can cancel the common factor

    • one year ago
  7. SmokeysTheName
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    you're left with t-4/t-6 right? :D

    • one year ago
  8. UnkleRhaukus
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    YES!

    • one year ago
  9. AravindG
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    well done @SmokeysTheName :D

    • one year ago
  10. SmokeysTheName
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    thank you (: now what do i do?

    • one year ago
  11. UnkleRhaukus
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    the restricted value for the variable \(t\) is the value that would make the denominator zero. this values is restricted because you can't divide by zero

    • one year ago
  12. SmokeysTheName
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    alright.. so do i have to put t+6 and t-6 equal to zero?

    • one year ago
  13. UnkleRhaukus
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    um, just the denominator ( the bottom bit of the fraction )

    • one year ago
  14. SmokeysTheName
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    yeah thats what i was talking about lol. okay so the restrictions would be -6 and +6 right?

    • one year ago
  15. UnkleRhaukus
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    after you have simplified , not before

    • one year ago
  16. SmokeysTheName
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    oh so just +6?

    • one year ago
  17. UnkleRhaukus
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    That's right \[\checkmark\]

    • one year ago
  18. SmokeysTheName
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    thank you!! (: that helps me a lot. do you mind helping me with a different question i am stuck on?

    • one year ago
  19. UnkleRhaukus
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    we can write this as \(t≠6\) , or we could say that \(t\) is defined on the domain \[(-∞,6)\cup(6,∞)\]

    • one year ago
  20. SmokeysTheName
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    oh that looks confusing.. (the second part)

    • one year ago
  21. UnkleRhaukus
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    if you haven't learnt that notation yet , just say that \(t≠6\) is the restriction they mean the same thing.

    • one year ago
  22. SmokeysTheName
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    oh okay. thank you (: can you help me on another question?

    • one year ago
  23. UnkleRhaukus
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    um Yes.

    • one year ago
  24. SmokeysTheName
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    Find the least common multiple of y^2 – 2y – 15 and y^2 – 7y + 10. how do i do this? im not sure how to do lcm

    • one year ago
  25. UnkleRhaukus
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    factorise those expressions,

    • one year ago
  26. SmokeysTheName
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    ok one sec.

    • one year ago
  27. SmokeysTheName
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    okay for the first equation i got (x-5)(x+3) and for the second equation i got (x-5)(x-2) . is that right? Or no..

    • one year ago
  28. UnkleRhaukus
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    you are good at factorising .that is right

    • one year ago
  29. SmokeysTheName
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    awh thank you (: in these types of problems i never know where to start. just like the other problem... anyways, is the least common multiple like x-5? or is that wrong ? i always get confused with lcm

    • one year ago
  30. UnkleRhaukus
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    now lets consider a simpler example say we were looking for the lcm of 6 and 4 we would factorise 6=2x3 & 4=2x2 the lcm is the product of the non-common factors so 2x3x2 (one of the twos is common) which equals 12

    • one year ago
  31. UnkleRhaukus
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    so to find the lcm of (x-5)(x+3) & (x-5)(x-2) multiple the factors ( and dont repeat common factors )

    • one year ago
  32. SmokeysTheName
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    ohh ok . so with my problem it would be (x-5)(x+3)(x-2) right? :D

    • one year ago
  33. UnkleRhaukus
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    YES!!!

    • one year ago
  34. SmokeysTheName
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    :D that makes me excited. i cant thank you enough !(:

    • one year ago
  35. UnkleRhaukus
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    you've be great to work with smokey .

    • one year ago
  36. SmokeysTheName
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    thank you, you too! (: if i need anymore help i can ask you right?

    • one year ago
  37. UnkleRhaukus
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    well i have to sleep kinda soon , but next time you can link me to a question like this @UnkleRhaukus

    • one year ago
  38. SmokeysTheName
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    okk. (: i will most definitely do that! thank you again (:

    • one year ago
  39. AravindG
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    @SmokeysTheName as UnkleRhaukus told ,you are great to work with I felt the same in our previous questions :) happy to have users like you in OS .Happy openstudying!

    • one year ago
  40. SmokeysTheName
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    awwwwh thank you so much ! (: <3

    • one year ago
  41. AravindG
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    yw :)

    • one year ago
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