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Simplify the rational expression. State any restrictions on the variable
 one year ago
 one year ago
Simplify the rational expression. State any restrictions on the variable
 one year ago
 one year ago

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SmokeysTheNameBest ResponseYou've already chosen the best response.3
please help and explain.?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
can you factorise the numerator and the denominator ?
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
yeah gimme a sec lemme do that real quick
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
the numerator is (t+6)(t4) im not sure how to factor the denominator.. i always forget.. i think its (t+6)(t6)  am i right?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
good work, that is right . now you can cancel the common factor
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
you're left with t4/t6 right? :D
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
well done @SmokeysTheName :D
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
thank you (: now what do i do?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
the restricted value for the variable \(t\) is the value that would make the denominator zero. this values is restricted because you can't divide by zero
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
alright.. so do i have to put t+6 and t6 equal to zero?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
um, just the denominator ( the bottom bit of the fraction )
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
yeah thats what i was talking about lol. okay so the restrictions would be 6 and +6 right?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
after you have simplified , not before
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
That's right \[\checkmark\]
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
thank you!! (: that helps me a lot. do you mind helping me with a different question i am stuck on?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
we can write this as \(t≠6\) , or we could say that \(t\) is defined on the domain \[(∞,6)\cup(6,∞)\]
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
oh that looks confusing.. (the second part)
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
if you haven't learnt that notation yet , just say that \(t≠6\) is the restriction they mean the same thing.
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
oh okay. thank you (: can you help me on another question?
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
Find the least common multiple of y^2 – 2y – 15 and y^2 – 7y + 10. how do i do this? im not sure how to do lcm
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
factorise those expressions,
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
okay for the first equation i got (x5)(x+3) and for the second equation i got (x5)(x2) . is that right? Or no..
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
you are good at factorising .that is right
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
awh thank you (: in these types of problems i never know where to start. just like the other problem... anyways, is the least common multiple like x5? or is that wrong ? i always get confused with lcm
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
now lets consider a simpler example say we were looking for the lcm of 6 and 4 we would factorise 6=2x3 & 4=2x2 the lcm is the product of the noncommon factors so 2x3x2 (one of the twos is common) which equals 12
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
so to find the lcm of (x5)(x+3) & (x5)(x2) multiple the factors ( and dont repeat common factors )
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
ohh ok . so with my problem it would be (x5)(x+3)(x2) right? :D
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
:D that makes me excited. i cant thank you enough !(:
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
you've be great to work with smokey .
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
thank you, you too! (: if i need anymore help i can ask you right?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.5
well i have to sleep kinda soon , but next time you can link me to a question like this @UnkleRhaukus
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
okk. (: i will most definitely do that! thank you again (:
 one year ago

AravindGBest ResponseYou've already chosen the best response.0
@SmokeysTheName as UnkleRhaukus told ,you are great to work with I felt the same in our previous questions :) happy to have users like you in OS .Happy openstudying!
 one year ago

SmokeysTheNameBest ResponseYou've already chosen the best response.3
awwwwh thank you so much ! (: <3
 one year ago
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