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Kayy_Drizzyy

  • one year ago

PlEASE HELP ? I can't manage to find the correct answer in my graphing calulator (PICTURE BELOW)

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  1. Kayy_Drizzyy
    • one year ago
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  2. Kayy_Drizzyy
    • one year ago
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    @UnkleRhaukus Can you help me please

  3. Kayy_Drizzyy
    • one year ago
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    @zordoloom Can you help me please

  4. zordoloom
    • one year ago
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    The proper graph is on graphcd.jpg.

  5. zordoloom
    • one year ago
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    So the second attachement, first image.

  6. Kayy_Drizzyy
    • one year ago
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    Oh okay, but i got a different answer on my graph cal. I feel like its messed up or something

  7. zordoloom
    • one year ago
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    Make sure you put parentheses.

  8. zordoloom
    • one year ago
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    Actually, wait one sec.

  9. AravindG
    • one year ago
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    i can lend you my graphing calculator http://www.wolframalpha.com/

  10. Kayy_Drizzyy
    • one year ago
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    Aww thanks @AravindG

  11. AravindG
    • one year ago
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    yw :)

  12. zordoloom
    • one year ago
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    On the first attachement, is there an intersection at y=-10?

  13. zordoloom
    • one year ago
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    It looks like the first attachement, graph 2.

  14. Kayy_Drizzyy
    • one year ago
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    @zordoloom I think its under the -10, but it is by it. & im checking in my cal. now

  15. zordoloom
    • one year ago
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    Okay, Its the on the first attachement, graph 2 then.

  16. Kayy_Drizzyy
    • one year ago
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    How did you get that answr ?

  17. zordoloom
    • one year ago
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    I graphed the graph and found its derivative. And it has an intersection below -10.

  18. Kayy_Drizzyy
    • one year ago
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    oh okay so if we look back is my answer A ?

  19. zordoloom
    • one year ago
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    No

  20. Kayy_Drizzyy
    • one year ago
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    :( What is it ?

  21. zordoloom
    • one year ago
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    I think it would be b. Because its the second graph on the first attachment. They aren't lettered, so I don't really know.

  22. Kayy_Drizzyy
    • one year ago
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    Ill show you one at a time.

  23. zordoloom
    • one year ago
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    1 Attachment
  24. Kayy_Drizzyy
    • one year ago
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    Yeah thats b Are you 100% sure ?

  25. Kayy_Drizzyy
    • one year ago
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    I'm about to try and graph it one more time

  26. zordoloom
    • one year ago
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    Yes, Positive.

  27. Kayy_Drizzyy
    • one year ago
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    Thankyou. Do you think you can help me with another problem im having trouble with ?

  28. zordoloom
    • one year ago
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    Sure.

  29. zordoloom
    • one year ago
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    So, was it correct?

  30. Kayy_Drizzyy
    • one year ago
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    1 Attachment
  31. zordoloom
    • one year ago
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    Give me a moment.

  32. zordoloom
    • one year ago
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    Okay, it's either the first one, or the third one.

  33. Kayy_Drizzyy
    • one year ago
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    How do you know that ?

  34. zordoloom
    • one year ago
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    Take the limit as x goes to 0.

  35. zordoloom
    • one year ago
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    Is this by any chance calculus?

  36. Kayy_Drizzyy
    • one year ago
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    No

  37. zordoloom
    • one year ago
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    Its the first one.

  38. Kayy_Drizzyy
    • one year ago
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    I still don't understand lol How did you get that ? can you please show me.

  39. zordoloom
    • one year ago
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    Have you studied limits?

  40. Kayy_Drizzyy
    • one year ago
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    Yes i took notes & i'm looking over them now, but i just need just a little help of how you got that.

  41. Kayy_Drizzyy
    • one year ago
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    are you 100% sure its the first one.

  42. zordoloom
    • one year ago
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    Sure. So you start by multiplying everything out. Then canceling like factors and you get the first and third choice.

  43. zordoloom
    • one year ago
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    Yes, 100%.

  44. zordoloom
    • one year ago
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    So the only option left is the first one.

  45. Kayy_Drizzyy
    • one year ago
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    Im working out the problem. & thank you :)

  46. zordoloom
    • one year ago
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    Another easy way to figure this out really fast is by looking at the options that are give. You can then determine that the only possible restriction is x can't equal 1. Everything else works.

  47. Kayy_Drizzyy
    • one year ago
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    Thank you so much . I'll keep that in mind. Do you have time for another problem you can help me ?

  48. zordoloom
    • one year ago
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    So plug it into your calculator, and plug x=1, You'll not get a solution there, since there is a vertical asympotoe.

  49. zordoloom
    • one year ago
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    Sure.

  50. Kayy_Drizzyy
    • one year ago
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  51. Kayy_Drizzyy
    • one year ago
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    @zordoloom

  52. zordoloom
    • one year ago
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    Still loooking at it.

  53. Kayy_Drizzyy
    • one year ago
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    Me to . I'm adleasttrying to work it out to see if i get the right answer.

  54. zordoloom
    • one year ago
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    Is that a 6b in the denominator?

  55. zordoloom
    • one year ago
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    That's defiantly a typo. it should be n.

  56. Kayy_Drizzyy
    • one year ago
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    Say what now ?

  57. zordoloom
    • one year ago
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    Assuming it's a typo, the correct answer is the second one.

  58. zordoloom
    • one year ago
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    The b in the denominator is a typo, a mistake. There is no answer with a b in it, therefore no solution exist. But if you replace the "b" with a "n" you get the second choice that is listed.

  59. Kayy_Drizzyy
    • one year ago
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    I got that to well almost. Kinda of similar. Can you please Show me work on how you got that so i can write it down and comapre it mine.

  60. zordoloom
    • one year ago
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    Do you not trust me?

  61. Kayy_Drizzyy
    • one year ago
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    I do haha, but im very aware of my grades and answers so i will ask are you 100% lol sorry

  62. Kayy_Drizzyy
    • one year ago
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    Your a big help & i wanna thank you

  63. zordoloom
    • one year ago
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    100%. but again there is a mistake in the question.

  64. AravindG
    • one year ago
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    @zordoloom a better idea would hav been guiding her to that solution instead of pointing out which option is right ..that way she could have understood it 100%

  65. zordoloom
    • one year ago
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    You start by factoring the top part and get (x+1)(x+2)

  66. Kayy_Drizzyy
    • one year ago
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    I dont see a typo. Im checking over my answer on my paper just to double check.

  67. AravindG
    • one year ago
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    @Kayy_Drizzyy did you like my calculator ? :)

  68. zordoloom
    • one year ago
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    And then factor the denominator and get (x+2)(x+4)

  69. Kayy_Drizzyy
    • one year ago
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    Alright @zordoloom Thanks a lot you were a lot of help.

  70. zordoloom
    • one year ago
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    |dw:1359126064965:dw|

  71. Kayy_Drizzyy
    • one year ago
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    Okay i see . I'm writting it down.

  72. zordoloom
    • one year ago
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    |dw:1359126148210:dw|

  73. Kayy_Drizzyy
    • one year ago
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    Are you good with complex fractions ? & thank you i understand that problem now .

  74. zordoloom
    • one year ago
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    Maybe.

  75. zordoloom
    • one year ago
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    More complex than these?

  76. Kayy_Drizzyy
    • one year ago
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    well to be honest im TERRIBLE with this & you helping me with this problem will mean a lot.

  77. zordoloom
    • one year ago
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    I gotta go in 5 minutes.

  78. Kayy_Drizzyy
    • one year ago
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    awww man

  79. zordoloom
    • one year ago
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    So post the question.

  80. Kayy_Drizzyy
    • one year ago
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    1 Attachment
  81. zordoloom
    • one year ago
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    I would say its the last option.

  82. Kayy_Drizzyy
    • one year ago
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    You would say ? Lol are you sure? Do we need to review

  83. zordoloom
    • one year ago
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    I'm sure.

  84. zordoloom
    • one year ago
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    It's none of the first 3, that's for sure. So it must be the last one.

  85. zordoloom
    • one year ago
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    Were any of the previous answer wrong?

  86. zordoloom
    • one year ago
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    *answers.

  87. Kayy_Drizzyy
    • one year ago
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    I havent submited it yet. So im not sure. But you can go now. Thank you so much for your help.

  88. zordoloom
    • one year ago
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    Yep.

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