anonymous
  • anonymous
PlEASE HELP ? I can't manage to find the correct answer in my graphing calulator (PICTURE BELOW)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
anonymous
  • anonymous
@UnkleRhaukus Can you help me please
anonymous
  • anonymous
@zordoloom Can you help me please

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anonymous
  • anonymous
The proper graph is on graphcd.jpg.
anonymous
  • anonymous
So the second attachement, first image.
anonymous
  • anonymous
Oh okay, but i got a different answer on my graph cal. I feel like its messed up or something
anonymous
  • anonymous
Make sure you put parentheses.
anonymous
  • anonymous
Actually, wait one sec.
AravindG
  • AravindG
i can lend you my graphing calculator http://www.wolframalpha.com/
anonymous
  • anonymous
Aww thanks @AravindG
AravindG
  • AravindG
yw :)
anonymous
  • anonymous
On the first attachement, is there an intersection at y=-10?
anonymous
  • anonymous
It looks like the first attachement, graph 2.
anonymous
  • anonymous
@zordoloom I think its under the -10, but it is by it. & im checking in my cal. now
anonymous
  • anonymous
Okay, Its the on the first attachement, graph 2 then.
anonymous
  • anonymous
How did you get that answr ?
anonymous
  • anonymous
I graphed the graph and found its derivative. And it has an intersection below -10.
anonymous
  • anonymous
oh okay so if we look back is my answer A ?
anonymous
  • anonymous
No
anonymous
  • anonymous
:( What is it ?
anonymous
  • anonymous
I think it would be b. Because its the second graph on the first attachment. They aren't lettered, so I don't really know.
anonymous
  • anonymous
Ill show you one at a time.
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Yeah thats b Are you 100% sure ?
anonymous
  • anonymous
I'm about to try and graph it one more time
anonymous
  • anonymous
Yes, Positive.
anonymous
  • anonymous
Thankyou. Do you think you can help me with another problem im having trouble with ?
anonymous
  • anonymous
Sure.
anonymous
  • anonymous
So, was it correct?
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Give me a moment.
anonymous
  • anonymous
Okay, it's either the first one, or the third one.
anonymous
  • anonymous
How do you know that ?
anonymous
  • anonymous
Take the limit as x goes to 0.
anonymous
  • anonymous
Is this by any chance calculus?
anonymous
  • anonymous
No
anonymous
  • anonymous
Its the first one.
anonymous
  • anonymous
I still don't understand lol How did you get that ? can you please show me.
anonymous
  • anonymous
Have you studied limits?
anonymous
  • anonymous
Yes i took notes & i'm looking over them now, but i just need just a little help of how you got that.
anonymous
  • anonymous
are you 100% sure its the first one.
anonymous
  • anonymous
Sure. So you start by multiplying everything out. Then canceling like factors and you get the first and third choice.
anonymous
  • anonymous
Yes, 100%.
anonymous
  • anonymous
So the only option left is the first one.
anonymous
  • anonymous
Im working out the problem. & thank you :)
anonymous
  • anonymous
Another easy way to figure this out really fast is by looking at the options that are give. You can then determine that the only possible restriction is x can't equal 1. Everything else works.
anonymous
  • anonymous
Thank you so much . I'll keep that in mind. Do you have time for another problem you can help me ?
anonymous
  • anonymous
So plug it into your calculator, and plug x=1, You'll not get a solution there, since there is a vertical asympotoe.
anonymous
  • anonymous
Sure.
anonymous
  • anonymous
anonymous
  • anonymous
@zordoloom
anonymous
  • anonymous
Still loooking at it.
anonymous
  • anonymous
Me to . I'm adleasttrying to work it out to see if i get the right answer.
anonymous
  • anonymous
Is that a 6b in the denominator?
anonymous
  • anonymous
That's defiantly a typo. it should be n.
anonymous
  • anonymous
Say what now ?
anonymous
  • anonymous
Assuming it's a typo, the correct answer is the second one.
anonymous
  • anonymous
The b in the denominator is a typo, a mistake. There is no answer with a b in it, therefore no solution exist. But if you replace the "b" with a "n" you get the second choice that is listed.
anonymous
  • anonymous
I got that to well almost. Kinda of similar. Can you please Show me work on how you got that so i can write it down and comapre it mine.
anonymous
  • anonymous
Do you not trust me?
anonymous
  • anonymous
I do haha, but im very aware of my grades and answers so i will ask are you 100% lol sorry
anonymous
  • anonymous
Your a big help & i wanna thank you
anonymous
  • anonymous
100%. but again there is a mistake in the question.
AravindG
  • AravindG
@zordoloom a better idea would hav been guiding her to that solution instead of pointing out which option is right ..that way she could have understood it 100%
anonymous
  • anonymous
You start by factoring the top part and get (x+1)(x+2)
anonymous
  • anonymous
I dont see a typo. Im checking over my answer on my paper just to double check.
AravindG
  • AravindG
@Kayy_Drizzyy did you like my calculator ? :)
anonymous
  • anonymous
And then factor the denominator and get (x+2)(x+4)
anonymous
  • anonymous
Alright @zordoloom Thanks a lot you were a lot of help.
anonymous
  • anonymous
|dw:1359126064965:dw|
anonymous
  • anonymous
Okay i see . I'm writting it down.
anonymous
  • anonymous
|dw:1359126148210:dw|
anonymous
  • anonymous
Are you good with complex fractions ? & thank you i understand that problem now .
anonymous
  • anonymous
Maybe.
anonymous
  • anonymous
More complex than these?
anonymous
  • anonymous
well to be honest im TERRIBLE with this & you helping me with this problem will mean a lot.
anonymous
  • anonymous
I gotta go in 5 minutes.
anonymous
  • anonymous
awww man
anonymous
  • anonymous
So post the question.
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
I would say its the last option.
anonymous
  • anonymous
You would say ? Lol are you sure? Do we need to review
anonymous
  • anonymous
I'm sure.
anonymous
  • anonymous
It's none of the first 3, that's for sure. So it must be the last one.
anonymous
  • anonymous
Were any of the previous answer wrong?
anonymous
  • anonymous
*answers.
anonymous
  • anonymous
I havent submited it yet. So im not sure. But you can go now. Thank you so much for your help.
anonymous
  • anonymous
Yep.

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