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anonymous
 4 years ago
PlEASE HELP ?
I can't manage to find the correct answer in my graphing calulator
(PICTURE BELOW)
anonymous
 4 years ago
PlEASE HELP ? I can't manage to find the correct answer in my graphing calulator (PICTURE BELOW)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@UnkleRhaukus Can you help me please

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@zordoloom Can you help me please

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The proper graph is on graphcd.jpg.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So the second attachement, first image.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh okay, but i got a different answer on my graph cal. I feel like its messed up or something

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Make sure you put parentheses.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Actually, wait one sec.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0i can lend you my graphing calculator http://www.wolframalpha.com/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0On the first attachement, is there an intersection at y=10?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It looks like the first attachement, graph 2.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@zordoloom I think its under the 10, but it is by it. & im checking in my cal. now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, Its the on the first attachement, graph 2 then.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How did you get that answr ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I graphed the graph and found its derivative. And it has an intersection below 10.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay so if we look back is my answer A ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think it would be b. Because its the second graph on the first attachment. They aren't lettered, so I don't really know.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ill show you one at a time.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah thats b Are you 100% sure ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm about to try and graph it one more time

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thankyou. Do you think you can help me with another problem im having trouble with ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, it's either the first one, or the third one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How do you know that ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Take the limit as x goes to 0.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is this by any chance calculus?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I still don't understand lol How did you get that ? can you please show me.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Have you studied limits?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes i took notes & i'm looking over them now, but i just need just a little help of how you got that.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0are you 100% sure its the first one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sure. So you start by multiplying everything out. Then canceling like factors and you get the first and third choice.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So the only option left is the first one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Im working out the problem. & thank you :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Another easy way to figure this out really fast is by looking at the options that are give. You can then determine that the only possible restriction is x can't equal 1. Everything else works.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you so much . I'll keep that in mind. Do you have time for another problem you can help me ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So plug it into your calculator, and plug x=1, You'll not get a solution there, since there is a vertical asympotoe.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Still loooking at it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Me to . I'm adleasttrying to work it out to see if i get the right answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Is that a 6b in the denominator?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's defiantly a typo. it should be n.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Assuming it's a typo, the correct answer is the second one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The b in the denominator is a typo, a mistake. There is no answer with a b in it, therefore no solution exist. But if you replace the "b" with a "n" you get the second choice that is listed.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got that to well almost. Kinda of similar. Can you please Show me work on how you got that so i can write it down and comapre it mine.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I do haha, but im very aware of my grades and answers so i will ask are you 100% lol sorry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Your a big help & i wanna thank you

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0100%. but again there is a mistake in the question.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0@zordoloom a better idea would hav been guiding her to that solution instead of pointing out which option is right ..that way she could have understood it 100%

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You start by factoring the top part and get (x+1)(x+2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I dont see a typo. Im checking over my answer on my paper just to double check.

AravindG
 4 years ago
Best ResponseYou've already chosen the best response.0@Kayy_Drizzyy did you like my calculator ? :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And then factor the denominator and get (x+2)(x+4)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Alright @zordoloom Thanks a lot you were a lot of help.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1359126064965:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay i see . I'm writting it down.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1359126148210:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Are you good with complex fractions ? & thank you i understand that problem now .

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0More complex than these?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well to be honest im TERRIBLE with this & you helping me with this problem will mean a lot.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I gotta go in 5 minutes.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So post the question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would say its the last option.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You would say ? Lol are you sure? Do we need to review

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's none of the first 3, that's for sure. So it must be the last one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Were any of the previous answer wrong?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I havent submited it yet. So im not sure. But you can go now. Thank you so much for your help.
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