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Tainted

  • 3 years ago

Medal will be given! How many grams of water vapor (H2O) are in a 10.2 liter sample at 0.98 atmospheres and 26°C? Show all work used to solve this problem

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  1. BrittanyFrench
    • 3 years ago
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    I'm trying to figure it out.. I just did stuff like this in my Chemistry class

  2. evergirl
    • 3 years ago
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    i have no idea O.o i don't have chemistry...

  3. BrittanyFrench
    • 3 years ago
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    Oakay, well what I know is all temperatures should be in Kelvin not Celsius..

  4. BrittanyFrench
    • 3 years ago
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    I'm trying to remember if you add 240 or 270

  5. BrittanyFrench
    • 3 years ago
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    Wow why am I having trouble with this, I'm struggling i'm not sure how to do this, I can't remember

  6. BrittanyFrench
    • 3 years ago
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    can you tell me what you're trying to find?

  7. Tainted
    • 3 years ago
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    n=pV/RT 1 mole of h2O = 18g 18*n= x grams

  8. BrittanyFrench
    • 3 years ago
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    oh you're doing mole stuff yucky, hold up I'm going thru my notes

  9. BrittanyFrench
    • 3 years ago
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    I'm sorry I do not know..

  10. JFraser
    • 3 years ago
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    To convert C into K, add 273. Plug into the ideal gas law and solve for moles of water. convert moles of water into grams of water

  11. Tainted
    • 3 years ago
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    Like so? m = PVM / RT R = (1atm x 22.4L) / (1mole x 273K) = 0.0821Latm/moleK T = 26 + 273 = 299K m = 0.98atm x 10.2L x 18g/mole / (0.0821Latm/molek x 299K) = 7.33gH2O

  12. JFraser
    • 3 years ago
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    i get about 7.5g, but that's close enough, given differences in rounding

  13. Tainted
    • 3 years ago
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    Ok thanks!

  14. JFraser
    • 3 years ago
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    yw

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