## Tainted 2 years ago Medal will be given! How many grams of water vapor (H2O) are in a 10.2 liter sample at 0.98 atmospheres and 26°C? Show all work used to solve this problem

1. BrittanyFrench

I'm trying to figure it out.. I just did stuff like this in my Chemistry class

2. evergirl

i have no idea O.o i don't have chemistry...

3. BrittanyFrench

Oakay, well what I know is all temperatures should be in Kelvin not Celsius..

4. BrittanyFrench

I'm trying to remember if you add 240 or 270

5. BrittanyFrench

Wow why am I having trouble with this, I'm struggling i'm not sure how to do this, I can't remember

6. BrittanyFrench

can you tell me what you're trying to find?

7. Tainted

n=pV/RT 1 mole of h2O = 18g 18*n= x grams

8. BrittanyFrench

oh you're doing mole stuff yucky, hold up I'm going thru my notes

9. BrittanyFrench

I'm sorry I do not know..

10. JFraser

To convert C into K, add 273. Plug into the ideal gas law and solve for moles of water. convert moles of water into grams of water

11. Tainted

Like so? m = PVM / RT R = (1atm x 22.4L) / (1mole x 273K) = 0.0821Latm/moleK T = 26 + 273 = 299K m = 0.98atm x 10.2L x 18g/mole / (0.0821Latm/molek x 299K) = 7.33gH2O

12. JFraser

i get about 7.5g, but that's close enough, given differences in rounding

13. Tainted

Ok thanks!

14. JFraser

yw