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BMF96
Group Title
r = 6 sinθ
Part I: Multiply both sides of this equation by r and use the fact that to rewrite this equation in terms of x and y.
I got x^2 + y^2 = 6y
Part II: Complete the square to produce the final equation.
Part III: Using only your answer to part II, what shape does this graph make?
 one year ago
 one year ago
BMF96 Group Title
r = 6 sinθ Part I: Multiply both sides of this equation by r and use the fact that to rewrite this equation in terms of x and y. I got x^2 + y^2 = 6y Part II: Complete the square to produce the final equation. Part III: Using only your answer to part II, what shape does this graph make?
 one year ago
 one year ago

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LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
So you want to move 6y over to the left side to obtain: x^2 + y^2 + 6y = 0 Then complete the square for the y variables. To do this, you'd take 6, divide it by 2, then square the result. You should end up with 9. dw:1359140495765:dw
 one year ago

BMF96 Group TitleBest ResponseYou've already chosen the best response.1
I don't completely understand. What is the final equation? x^2 + (y+3)^2  9?
 one year ago

BMF96 Group TitleBest ResponseYou've already chosen the best response.1
which seems to simplify to x^2 + y^2
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
No, you simply completed the square. There is no way to simplify it to x^2 + y^2. However, if you remember, your equation is now equal to 0. x^2 + (y + 3)^2  9 = 0 Add 9 to both sides and see if you recognize this type of equation.
 one year ago

BMF96 Group TitleBest ResponseYou've already chosen the best response.1
looks like a circle with the origin at 3
 one year ago

BMF96 Group TitleBest ResponseYou've already chosen the best response.1
and radius of 3
 one year ago

LogicalApple Group TitleBest ResponseYou've already chosen the best response.1
Right. A circle centered at (0, 3) with radius 3. And that's all there is to it :)
 one year ago

BMF96 Group TitleBest ResponseYou've already chosen the best response.1
Right, Thanks!
 one year ago
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