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JakeM

  • 3 years ago

An engine piston has a diameter of 9.2 cm, with a tolerance of 0.01 cm. Which absolute value inequality represents the range of values for the diameter of the piston? A. |x – 9.2| 0.01 B. |x – 9.2| 0.01 C. |x – 0.01| 9.2 D. |x – 0.01| 9.2

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  1. LogicalApple
    • 3 years ago
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    I do not see the outputs correctly -- A and B look identical, and C and D look identical. But for this question, the tolerance is telling us that the actual diameter of the engine is no more than 9.2 + 0.01 cm and now less than 9.2 - 0.01 cm. Thus the range of values of the actual diameter is 9.19 cm - 9.21 cm Another way of phrasing this is letting 'x' denote the actual value of the diameter and then limiting 'x' to being within 0.01 cm of 9.2: |x - 9.2| <= 0.01 Which is identical to -0.01 <= x - 9.2 <= 0.01 Or . . . 9.19 <= x <= 9.21 I hope this help :)

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