anonymous
  • anonymous
What is the domain of the function shown below? f(x)=-24/(x^2+8) help please
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@Mertsj or @phi can you guys help?
anonymous
  • anonymous
well the domain are the x values for which the function is defined. for a fraction such as yours to be undefined the divisor must be 0 but x^2+8 > 0 for every x so the domain is R, every real number
Mertsj
  • Mertsj
Remember, the denominator cannot be 0. Since the denominator is x^2+8, and x^2 has a smallest value of 0, and 0+8 will always be positive, there are no restrictions on x and the domain is all real numbers.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
hey Mertsj, can you help me with some advanced number theory? i am trying to do something with the sigma function(sum of divisors of number)
anonymous
  • anonymous
so then the domain would be all real numbers greater than 0?
anonymous
  • anonymous
yes
anonymous
  • anonymous
dag nabit it was just all real numbers :/ thanks anyways
Mertsj
  • Mertsj
Didn't I post that the domain is all real numbers?

Looking for something else?

Not the answer you are looking for? Search for more explanations.