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sat_chen

  • 3 years ago

integration of (sin^5x)*(cos^3x)dx

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  1. hartnn
    • 3 years ago
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    split cos^3 x = cos x * cos^2 x write cos^2 x = 1- sin^2 x then its easy to see that u = sin x du =cos x dx.

  2. sat_chen
    • 3 years ago
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    so do you leave sin^5x as it is

  3. hartnn
    • 3 years ago
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    yes, then you'll use it... s^5 (1-s^2) c dx [s=sin, c=cos]

  4. hartnn
    • 3 years ago
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    s^5 (1-s^2) c dx = (s^5 -s^7) cdx

  5. sat_chen
    • 3 years ago
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    ah i see how that tricked me i tried to think it was a half angle formula or something

  6. hartnn
    • 3 years ago
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    so, now can you solve that integral ?

  7. sat_chen
    • 3 years ago
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    yea i can thanks a lot bro

  8. hartnn
    • 3 years ago
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    welcome ^_^

  9. sat_chen
    • 3 years ago
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    math not my best subject :P

  10. hartnn
    • 3 years ago
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    it became my best subject, after lot of practicing :)

  11. sat_chen
    • 3 years ago
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    1 question though can you split sin of x to solve also

  12. hartnn
    • 3 years ago
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    yes,but that will be more complicated....but yes.

  13. sat_chen
    • 3 years ago
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    ah i see ty again

  14. sat_chen
    • 3 years ago
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    if i need help again asking you :P

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