Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

integration of (sin^5x)*(cos^3x)dx

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

split cos^3 x = cos x * cos^2 x write cos^2 x = 1- sin^2 x then its easy to see that u = sin x du =cos x dx.
so do you leave sin^5x as it is
yes, then you'll use it... s^5 (1-s^2) c dx [s=sin, c=cos]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

s^5 (1-s^2) c dx = (s^5 -s^7) cdx
ah i see how that tricked me i tried to think it was a half angle formula or something
so, now can you solve that integral ?
yea i can thanks a lot bro
welcome ^_^
math not my best subject :P
it became my best subject, after lot of practicing :)
1 question though can you split sin of x to solve also
yes,but that will be more complicated....but yes.
ah i see ty again
if i need help again asking you :P

Not the answer you are looking for?

Search for more explanations.

Ask your own question