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so do you leave sin^5x as it is

yes,
then you'll use it...
s^5 (1-s^2) c dx [s=sin, c=cos]

s^5 (1-s^2) c dx = (s^5 -s^7) cdx

ah i see how that tricked me i tried to think it was a half angle formula or something

so, now can you solve that integral ?

yea i can thanks a lot bro

welcome ^_^

math not my best subject :P

it became my best subject, after lot of practicing :)

1 question though can you split sin of x to solve also

yes,but that will be more complicated....but yes.

ah i see ty again

if i need help again asking you :P