## Bladerunner1122 2 years ago Find the average value of the function f on the given interval. f(x)=1/x^2 on the interval [1,5] I'll draw what I've got so far.

1. abb0t

Take the integral of x^-2 from 1<x<5

|dw:1359149773019:dw|

What is the next step?

4. abb0t

$\frac{ 1 }{ 4 }\left[ -\frac{ 1 }{ 5 } - \left( -\frac{ 1 }{ 1 } \right) \right]=$

Thank you that helps me a bunch! So the answer is 1/5 and now I know the

process.

7. abb0t

Read up on the fundamental theorem of Calculus II. It explains this clearly.