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 one year ago
Find the average value of the function f on the given interval.
f(x)=1/x^2 on the interval [1,5]
I'll draw what I've got so far.
 one year ago
Find the average value of the function f on the given interval. f(x)=1/x^2 on the interval [1,5] I'll draw what I've got so far.

This Question is Closed

abb0t
 one year ago
Best ResponseYou've already chosen the best response.1Take the integral of x^2 from 1<x<5

Bladerunner1122
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359149773019:dw

Bladerunner1122
 one year ago
Best ResponseYou've already chosen the best response.0What is the next step?

abb0t
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 1 }{ 4 }\left[ \frac{ 1 }{ 5 }  \left( \frac{ 1 }{ 1 } \right) \right]=\]

Bladerunner1122
 one year ago
Best ResponseYou've already chosen the best response.0Thank you that helps me a bunch! So the answer is 1/5 and now I know the

abb0t
 one year ago
Best ResponseYou've already chosen the best response.1Read up on the fundamental theorem of Calculus II. It explains this clearly.
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