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Bladerunner1122

  • one year ago

Find the average value of the function f on the given interval. f(x)=1/x^2 on the interval [1,5] I'll draw what I've got so far.

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  1. abb0t
    • one year ago
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    Take the integral of x^-2 from 1<x<5

  2. Bladerunner1122
    • one year ago
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    |dw:1359149773019:dw|

  3. Bladerunner1122
    • one year ago
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    What is the next step?

  4. abb0t
    • one year ago
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    \[\frac{ 1 }{ 4 }\left[ -\frac{ 1 }{ 5 } - \left( -\frac{ 1 }{ 1 } \right) \right]=\]

  5. Bladerunner1122
    • one year ago
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    Thank you that helps me a bunch! So the answer is 1/5 and now I know the

  6. Bladerunner1122
    • one year ago
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    process.

  7. abb0t
    • one year ago
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    Read up on the fundamental theorem of Calculus II. It explains this clearly.

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