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Find the average value of the function f on the given interval. f(x)=1/x^2 on the interval [1,5] I'll draw what I've got so far.

Mathematics
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Take the integral of x^-2 from 1
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What is the next step?

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Other answers:

\[\frac{ 1 }{ 4 }\left[ -\frac{ 1 }{ 5 } - \left( -\frac{ 1 }{ 1 } \right) \right]=\]
Thank you that helps me a bunch! So the answer is 1/5 and now I know the
process.
Read up on the fundamental theorem of Calculus II. It explains this clearly.

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