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take the integration of (sin5x)*(sin3x)dx

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first sin5x sin 3x =-1/2{cos(5x+3x) - cos (5x-3x)}
how in the gods name did you get that

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Other answers:

the only trick we know so far are the trigonometric identities and half angle formula
so confused ...
understand ? i use product to sum formula
oh okay thanks
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ive never seen that format of sum for sine before thanks. is there other ways to do it or is that it
other way is to expand sin 5x ,sin 3x but its harder i send there formula 4 you
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i guess ill have to remember the sum rule then :P
the other one you sent is not gonna be much help in the long run probably. thanks a lot though
and 3st way write sin5x=sin4x+x and sin 3x=sin4x-x so you have conjugate union if expand them it is easier than 2nd way (that i said)

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