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sat_chen

  • 2 years ago

take the integration of (sin5x)*(sin3x)dx

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  1. amoodarya
    • 2 years ago
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    first sin5x sin 3x =-1/2{cos(5x+3x) - cos (5x-3x)}

  2. sat_chen
    • 2 years ago
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    how in the gods name did you get that

  3. amoodarya
    • 2 years ago
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    |dw:1359154820627:dw|

  4. sat_chen
    • 2 years ago
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    the only trick we know so far are the trigonometric identities and half angle formula

  5. sat_chen
    • 2 years ago
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    so confused ...

  6. amoodarya
    • 2 years ago
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    understand ? i use product to sum formula

  7. sat_chen
    • 2 years ago
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    oh okay thanks

  8. amoodarya
    • 2 years ago
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  9. sat_chen
    • 2 years ago
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    ive never seen that format of sum for sine before thanks. is there other ways to do it or is that it

  10. amoodarya
    • 2 years ago
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    other way is to expand sin 5x ,sin 3x but its harder i send there formula 4 you

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  11. sat_chen
    • 2 years ago
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    i guess ill have to remember the sum rule then :P

  12. sat_chen
    • 2 years ago
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    the other one you sent is not gonna be much help in the long run probably. thanks a lot though

  13. amoodarya
    • 2 years ago
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    and 3st way write sin5x=sin4x+x and sin 3x=sin4x-x so you have conjugate union if expand them it is easier than 2nd way (that i said)

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