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orbie
 2 years ago
Solve the equation by any method.
x^(2)+√(5x)2=0
Which method could I use for this problem?
orbie
 2 years ago
Solve the equation by any method. x^(2)+√(5x)2=0 Which method could I use for this problem?

This Question is Closed

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.0A good thing to do first would be to get rid of your square root by sending it to the other side of the equality, then square both sides

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0Hmm I'm not sure how you would approach this one... http://www.wolframalpha.com/input/?i=x%5E2%2B%285x%29%5E%281%2F2%292%3D0 If you go down to where it says "Real Solution:" Click the box that changes it to exact form, you'll see that the answer is crazy _

kirbykirby
 2 years ago
Best ResponseYou've already chosen the best response.0LOL haha. Yeah indeed it appears this one would be tricky as @zepdrix has shown..

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1...unless you just wrote it incorrectly. Did you mean \(\sqrt{5}x\) or did you REALLY mean \(\sqrt{5x}\)? Very different animals.

orbie
 2 years ago
Best ResponseYou've already chosen the best response.0Ah! Crap.... I wrote it wrong you where right @tkhunny its supposed to not include x in it. Thank you for pointing that out

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1Perfect. Did you try the Quadratic Formula?

orbie
 2 years ago
Best ResponseYou've already chosen the best response.0Okay I did that and I don't know. That radical is annoying me. Not sure if this is right but I got \[\frac{ \sqrt{5}\pm \sqrt{13} }{ 2 }\] ?

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1When you start with irrational coefficients, you should expect that. Only a miracle will clear it out to integers for you.

orbie
 2 years ago
Best ResponseYou've already chosen the best response.0Ah I got it right! Yay! Thank you everyone.
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