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Solve the equation by any method.
x^(2)+√(5x)2=0
Which method could I use for this problem?
 one year ago
 one year ago
Solve the equation by any method. x^(2)+√(5x)2=0 Which method could I use for this problem?
 one year ago
 one year ago

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kirbykirbyBest ResponseYou've already chosen the best response.0
A good thing to do first would be to get rid of your square root by sending it to the other side of the equality, then square both sides
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
Hmm I'm not sure how you would approach this one... http://www.wolframalpha.com/input/?i=x%5E2%2B%285x%29%5E%281%2F2%292%3D0 If you go down to where it says "Real Solution:" Click the box that changes it to exact form, you'll see that the answer is crazy _
 one year ago

kirbykirbyBest ResponseYou've already chosen the best response.0
LOL haha. Yeah indeed it appears this one would be tricky as @zepdrix has shown..
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
...unless you just wrote it incorrectly. Did you mean \(\sqrt{5}x\) or did you REALLY mean \(\sqrt{5x}\)? Very different animals.
 one year ago

orbieBest ResponseYou've already chosen the best response.0
Ah! Crap.... I wrote it wrong you where right @tkhunny its supposed to not include x in it. Thank you for pointing that out
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
Perfect. Did you try the Quadratic Formula?
 one year ago

orbieBest ResponseYou've already chosen the best response.0
Okay I did that and I don't know. That radical is annoying me. Not sure if this is right but I got \[\frac{ \sqrt{5}\pm \sqrt{13} }{ 2 }\] ?
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.1
When you start with irrational coefficients, you should expect that. Only a miracle will clear it out to integers for you.
 one year ago

orbieBest ResponseYou've already chosen the best response.0
Ah I got it right! Yay! Thank you everyone.
 one year ago
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