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orbie

  • 3 years ago

Solve the equation by any method. x^(2)+√(5x)-2=0 Which method could I use for this problem?

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  1. kirbykirby
    • 3 years ago
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    A good thing to do first would be to get rid of your square root by sending it to the other side of the equality, then square both sides

  2. zepdrix
    • 3 years ago
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    Hmm I'm not sure how you would approach this one... http://www.wolframalpha.com/input/?i=x%5E2%2B%285x%29%5E%281%2F2%29-2%3D0 If you go down to where it says "Real Solution:" Click the box that changes it to exact form, you'll see that the answer is crazy -_-

  3. kirbykirby
    • 3 years ago
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    LOL haha. Yeah indeed it appears this one would be tricky as @zepdrix has shown..

  4. tkhunny
    • 3 years ago
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    ...unless you just wrote it incorrectly. Did you mean \(\sqrt{5}x\) or did you REALLY mean \(\sqrt{5x}\)? Very different animals.

  5. amoodarya
    • 3 years ago
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  6. orbie
    • 3 years ago
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    Ah! Crap.... I wrote it wrong you where right @tkhunny its supposed to not include x in it. Thank you for pointing that out

  7. tkhunny
    • 3 years ago
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    Perfect. Did you try the Quadratic Formula?

  8. amoodarya
    • 3 years ago
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    Quadratic Formula

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  9. orbie
    • 3 years ago
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    Okay I did that and I don't know. That radical is annoying me. Not sure if this is right but I got \[\frac{ -\sqrt{5}\pm \sqrt{13} }{ 2 }\] ?

  10. tkhunny
    • 3 years ago
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    When you start with irrational coefficients, you should expect that. Only a miracle will clear it out to integers for you.

  11. orbie
    • 3 years ago
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    Ah I got it right! Yay! Thank you everyone.

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