am i doing this integration right?
( wait like 2 min to draw my problem and solution steps) thanks

- anonymous

am i doing this integration right?
( wait like 2 min to draw my problem and solution steps) thanks

- jamiebookeater

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- anonymous

|dw:1359158701050:dw|

- anonymous

|dw:1359158759022:dw|

- anonymous

|dw:1359158787925:dw|

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## More answers

- anonymous

|dw:1359158816420:dw|

- anonymous

is that right sorry couldnt think of a better way

- anonymous

Looks good to me

- anonymous

last problem before im done for the week so can someone else verify ty

- anonymous

not that i dont respect you incompite :P

- abb0t

You could of separated it from the beginning first: \[\int\limits \frac{ \sec^2(x) }{ \tan^2(x) }dx - \int\limits \frac{ 1 }{ \tan^2(x) }dx \]
use u-substitution:
u = tan(x)
du = sec^2(x)
\[\int\limits \frac{ 1 }{ u^2 }du - \int\limits \frac{ 1 }{ \tan^2(x) }dx\]
and you know: \[\frac{ 1 }{ \tan^2(x) }= \frac{ 1 }{ \frac{ \sin^2(x) }{ \cos^2(x) } } = \frac{ \cos^2(x) }{ \sin^2(x) }= \cot^2(x)\]
proceed: \[\int\limits \cot^2(x)dx = -x-\cot(x)+C\]
PUT EVERYTHING TOGETHER:
\[-\frac{ 1 }{ \tan(x) }-(-x-\cot(x))+C\]

- anonymous

You got the questions wrong @abb0t . Its tan/sec not the other way around

- anonymous

you did the question wrong

- abb0t

omg. Lol. fudge.

- anonymous

well sorry for making you waste so much time :(

- anonymous

so was i right abb0t

- anonymous

i feel really bad for making you take so long and you got the question wrong really sorry next time ill make iit more clear :(

- anonymous

lol im pretty sure it is

- abb0t

mmk.

- anonymous

The int of sec^2 is tan. You dont need any other steps to compute that.

- anonymous

the sec^2x cancel out leaving 2/sec^2x which is 2ln(tanx) right

- anonymous

you cant just throw the 1 away. Its 1, not 0

- abb0t

am i looking @ the wrong question?! LOL

- anonymous

|dw:1359159907953:dw|

- anonymous

heres the question again

- anonymous

yea i do believe its right ty guys i feel bad for ab0t all that work :(

- anonymous

If your professors says its wrong, request to see where they got their degree from lol

- anonymous

my professor is a smart dude hes got masters at 21 so ill believe him if he says im wrong XD

- abb0t

lol. whoa watch out, we got a bada_ _!! JK he's human and still susceptible to mistakes.

- anonymous

Well im 4 months away too, in electrical engineering to be precise.

- anonymous

me too woot

- anonymous

im also ece

- anonymous

but im second year 19 so if i try hard enough i may get done by 21

- abb0t

i'm abt 2 graduate 8th grade.

- anonymous

avoided math as much as i could :P

- anonymous

hahahhaa

- anonymous

yea right abo0t

- anonymous

You prolly still have to take diffe eq, multi variate and statistics then. Good luck lol

- abb0t

Don't forget Linear Algebra.

- anonymous

So smart for someone who is in 8th grade

- anonymous

yea i do and i hate math so not the best major for me XD

- anonymous

i found abb0t secret http://www.youtube.com/watch?v=lXp7Ta1UmQA

- anonymous

hest that dude right there

- abb0t

omg. lol. i was guessing. geezbus. Lol

- anonymous

Dont give up though, the degree is hot cake once you graduate. I promise

- anonymous

i know thats why im keeping at it

- anonymous

and i know some people that got direct to intel from here for 100k + so im gonna work my retriceoff

- anonymous

butt off*

- anonymous

and hes 21 as well so should be a good life from then on :P

- anonymous

And that youtube guy is on a whole different level. As long as he can spit off derivatives and int from his head when he turns 18, otherwise he will be that one yotube guy

- anonymous

that was just a quick google search btw so im sure there are more genious of abb0t level ;)

- anonymous

haha bye all

- anonymous

u in us by the way

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