anonymous
  • anonymous
Help please? state the limit and if there is not limit say that limit doesn't exist.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1) lim x-> -1 f(x) 2) lim x-> 2- f(x) 3) lim x-> 2+ f(x) 4) lim x-> 2 f(x) 5) lim x-> -2 f(x) 6) lim x-> 3f(x)
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anonymous
  • anonymous
@Outkast3r09 can u help please?
anonymous
  • anonymous
@UnkleRhaukus can u help?

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UnkleRhaukus
  • UnkleRhaukus
\[\lim\limits_{ x\to -1} f(x)\] is the height of the blue line above x=-1 on the x-axis
UnkleRhaukus
  • UnkleRhaukus
\[\lim\limits_{ x\to 2^-} f(x)\] is the height of the blue line above the point just before 2 on the x axis
anonymous
  • anonymous
hmm ok
anonymous
  • anonymous
so for the first one it will be -2?
anonymous
  • anonymous
soo?
UnkleRhaukus
  • UnkleRhaukus
no. the blue line is crossing the axis at x=-1, so the height is zero here
anonymous
  • anonymous
ohh okay
anonymous
  • anonymous
so the limit will be zero?
UnkleRhaukus
  • UnkleRhaukus
yeah for the first one thats right
anonymous
  • anonymous
okay
anonymous
  • anonymous
lemme try the second one
anonymous
  • anonymous
so number 2 will be -1? right?
UnkleRhaukus
  • UnkleRhaukus
correct
anonymous
  • anonymous
ohh i think i'm starting to get this
anonymous
  • anonymous
hmm for number 3 will the open circle count?
anonymous
  • anonymous
or will it be undefined?
UnkleRhaukus
  • UnkleRhaukus
\[\lim\limits_{ x\to 2^+} f(x)\] is where x is a little bit to the right of 2 so is a tiny bit to the right of the open circle
UnkleRhaukus
  • UnkleRhaukus
if you were looking for the limit as \[x\to 2\] and both circles were open then it would be undefined
anonymous
  • anonymous
so it will be positive 2?
UnkleRhaukus
  • UnkleRhaukus
um check that again
anonymous
  • anonymous
ok
anonymous
  • anonymous
positive 1?
anonymous
  • anonymous
wait it will be -2
anonymous
  • anonymous
did i get it?
UnkleRhaukus
  • UnkleRhaukus
nope
anonymous
  • anonymous
okay i'm gonna try again
anonymous
  • anonymous
it will be -3
UnkleRhaukus
  • UnkleRhaukus
how could it be negative?
anonymous
  • anonymous
oh imeant positive 3
anonymous
  • anonymous
so is that correct?
UnkleRhaukus
  • UnkleRhaukus
thats better
anonymous
  • anonymous
ok so number 4 will be -1 ?
UnkleRhaukus
  • UnkleRhaukus
thats right, ( note that if the lower circle was open then it would be undefined)
anonymous
  • anonymous
okay number 5 will be -2?
UnkleRhaukus
  • UnkleRhaukus
nope
anonymous
  • anonymous
hmmm ohh ok so it will be undefined right?
UnkleRhaukus
  • UnkleRhaukus
im not sure how you are getting that/
anonymous
  • anonymous
let me look it again
anonymous
  • anonymous
it will be positive 2?
anonymous
  • anonymous
am i right?
UnkleRhaukus
  • UnkleRhaukus
it looks more like 1.5 to me
anonymous
  • anonymous
its close but it hasn't reached the line
anonymous
  • anonymous
ok
anonymous
  • anonymous
how about the last one? its tricky
UnkleRhaukus
  • UnkleRhaukus
what do you think
anonymous
  • anonymous
it will be it doesnt exist
anonymous
  • anonymous
right?
UnkleRhaukus
  • UnkleRhaukus
why would you say that
anonymous
  • anonymous
hmmm hold on
anonymous
  • anonymous
it will be 3?
anonymous
  • anonymous
did i get it?
UnkleRhaukus
  • UnkleRhaukus
a bit less
anonymous
  • anonymous
2?
anonymous
  • anonymous
soo?
anonymous
  • anonymous
are u there?
UnkleRhaukus
  • UnkleRhaukus
dosent look like 2 to me
UnkleRhaukus
  • UnkleRhaukus
look like about 2.5 to me
anonymous
  • anonymous
ok thanks

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