Help please? state the limit and if there is not limit say that limit doesn't exist.

- anonymous

Help please? state the limit and if there is not limit say that limit doesn't exist.

- katieb

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- anonymous

1) lim x-> -1 f(x)
2) lim x-> 2- f(x)
3) lim x-> 2+ f(x)
4) lim x-> 2 f(x)
5) lim x-> -2 f(x)
6) lim x-> 3f(x)

##### 1 Attachment

- anonymous

@Outkast3r09 can u help please?

- anonymous

@UnkleRhaukus can u help?

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## More answers

- UnkleRhaukus

\[\lim\limits_{ x\to -1} f(x)\]
is the height of the blue line above x=-1 on the x-axis

- UnkleRhaukus

\[\lim\limits_{ x\to 2^-} f(x)\]
is the height of the blue line above the point just before 2 on the x axis

- anonymous

hmm ok

- anonymous

so for the first one it will be -2?

- anonymous

soo?

- UnkleRhaukus

no. the blue line is crossing the axis at x=-1, so the height is zero here

- anonymous

ohh okay

- anonymous

so the limit will be zero?

- UnkleRhaukus

yeah for the first one thats right

- anonymous

okay

- anonymous

lemme try the second one

- anonymous

so number 2 will be -1? right?

- UnkleRhaukus

correct

- anonymous

ohh i think i'm starting to get this

- anonymous

hmm for number 3 will the open circle count?

- anonymous

or will it be undefined?

- UnkleRhaukus

\[\lim\limits_{ x\to 2^+} f(x)\] is where x is a little bit to the right of 2 so is a tiny bit to the right of the open circle

- UnkleRhaukus

if you were looking for the limit as \[x\to 2\] and both circles were open then it would be undefined

- anonymous

so it will be positive 2?

- UnkleRhaukus

um check that again

- anonymous

ok

- anonymous

positive 1?

- anonymous

wait it will be -2

- anonymous

did i get it?

- UnkleRhaukus

nope

- anonymous

okay i'm gonna try again

- anonymous

it will be -3

- UnkleRhaukus

how could it be negative?

- anonymous

oh imeant positive 3

- anonymous

so is that correct?

- UnkleRhaukus

thats better

- anonymous

ok so number 4 will be -1 ?

- UnkleRhaukus

thats right, ( note that if the lower circle was open then it would be undefined)

- anonymous

okay number 5 will be -2?

- UnkleRhaukus

nope

- anonymous

hmmm ohh ok so it will be undefined right?

- UnkleRhaukus

im not sure how you are getting that/

- anonymous

let me look it again

- anonymous

it will be positive 2?

- anonymous

am i right?

- UnkleRhaukus

it looks more like 1.5 to me

- anonymous

its close but it hasn't reached the line

- anonymous

ok

- anonymous

how about the last one? its tricky

- UnkleRhaukus

what do you think

- anonymous

it will be it doesnt exist

- anonymous

right?

- UnkleRhaukus

why would you say that

- anonymous

hmmm hold on

- anonymous

it will be 3?

- anonymous

did i get it?

- UnkleRhaukus

a bit less

- anonymous

2?

- anonymous

soo?

- anonymous

are u there?

- UnkleRhaukus

dosent look like 2 to me

- UnkleRhaukus

look like about 2.5 to me

- anonymous

ok thanks

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