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Help please? state the limit and if there is not limit say that limit doesn't exist.

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1) lim x-> -1 f(x) 2) lim x-> 2- f(x) 3) lim x-> 2+ f(x) 4) lim x-> 2 f(x) 5) lim x-> -2 f(x) 6) lim x-> 3f(x)
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@Outkast3r09 can u help please?
@UnkleRhaukus can u help?

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Other answers:

\[\lim\limits_{ x\to -1} f(x)\] is the height of the blue line above x=-1 on the x-axis
\[\lim\limits_{ x\to 2^-} f(x)\] is the height of the blue line above the point just before 2 on the x axis
hmm ok
so for the first one it will be -2?
no. the blue line is crossing the axis at x=-1, so the height is zero here
ohh okay
so the limit will be zero?
yeah for the first one thats right
lemme try the second one
so number 2 will be -1? right?
ohh i think i'm starting to get this
hmm for number 3 will the open circle count?
or will it be undefined?
\[\lim\limits_{ x\to 2^+} f(x)\] is where x is a little bit to the right of 2 so is a tiny bit to the right of the open circle
if you were looking for the limit as \[x\to 2\] and both circles were open then it would be undefined
so it will be positive 2?
um check that again
positive 1?
wait it will be -2
did i get it?
okay i'm gonna try again
it will be -3
how could it be negative?
oh imeant positive 3
so is that correct?
thats better
ok so number 4 will be -1 ?
thats right, ( note that if the lower circle was open then it would be undefined)
okay number 5 will be -2?
hmmm ohh ok so it will be undefined right?
im not sure how you are getting that/
let me look it again
it will be positive 2?
am i right?
it looks more like 1.5 to me
its close but it hasn't reached the line
how about the last one? its tricky
what do you think
it will be it doesnt exist
why would you say that
hmmm hold on
it will be 3?
did i get it?
a bit less
are u there?
dosent look like 2 to me
look like about 2.5 to me
ok thanks

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