solve for x 2In =(x+9) 0.4=log x 1=In(x+7) you invest 4,100 in an account that pays an interest rate of 7.5% compounded continuously. Calculate balance after of your account after 8 years? You invest 1,200 in an account that pays an interest rate of 7.25% compounded continuously calculate balance after 7 years.

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solve for x 2In =(x+9) 0.4=log x 1=In(x+7) you invest 4,100 in an account that pays an interest rate of 7.5% compounded continuously. Calculate balance after of your account after 8 years? You invest 1,200 in an account that pays an interest rate of 7.25% compounded continuously calculate balance after 7 years.

Algebra
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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instead of in put ln can you edit the question pls
0.4=log x \[0.4=\log_{10}x \implies 10^{0.4}=x\]
\[1=\ln(x+7) \implies e^1=e^{\ln(x+7)}\] use \[e^{\ln b}=b\]

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I did edit it but it stills shows upas in

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