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If possible, choose k so that the following function is continuous on any interval (equation in post).

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\[f(x)=\left[\begin{matrix}kcos(x), & x \le0 \\ 10e^{x}-k,&0< x \end{matrix}\right]\]
I haven't passed 4th grade math yet.

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Other answers:

Oh that's ok then (= thanks anyhow
do you know the basics of continuity ?
that the line must contiously go and still be a function (one to one) =P if that's what you mean
i meant, if f(x) is continuous, at x=0, \[\lim \limits{x \rightarrow 0^-} f(x)=\lim \limits{x \rightarrow 0^+f(x)}\]
do you you something like that ^ ?
for x->0- , since x<0, select k cos x and put x=0 for x->0+ , since x>0, select 10e^x-k and put x=0
Honestly that is all I know
when x->0-, lim kcos x = k cos 0 = k when x->0+, lim 10e^x-k = 10e^0-k =10- k for continuity k=10-k can you find k from here ?
just add k to both sides.

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