## mramirez686 2 years ago 90 coins in a jar of quarters and nickels. There is a total of \$15.10, how many nickels and how many quarters are in the jar? --so far, I have the 2X2 linear system set up as so: 15.10 = .05n + .25q 90 = .05n + .25q --is this correct? and how should I solve it, substitution or elimination? Thanks!

1. JayDS

seems correct but not correct to me.

2. JayDS

3. JayDS

because u can't solve it like that, u see the coefficients are the same in front of n and q? that makes it unsolvable.

4. mramirez686

Yes, I see that

5. mramirez686

which explains why I keep running in circles

6. JayDS

lol. sorry, I haven't done these type of questions in ages..

7. mramirez686

that's fine, at least I have a hint on a different direction. Thank you

8. JayDS

your welcome, let me see if I can ask others to help u.

9. mramirez686

perhaps?: 15.10 = .05n + .25q 90 = n + q since amount of quarters and nickels would be whole numbers, but money would be decimal

10. mramirez686

I believe that's it! There are 37 nickels and 53 quarters. Thanks for the nudge in the right direction. Sometimes it's the little things that help.

11. JayDS

yeh, that's what I thought but I wasn't too sure but it should work, yeh it looks right to me.

12. JayDS

at least I somehow helped lol.

13. mramirez686

haha, yeah, you have to know what you are doing wrong to fix it.

14. JayDS

haha true.

15. JayDS

but u also have to be the smart one to know where to fix it.