90 coins in a jar of quarters and nickels. There is a total of $15.10, how many nickels and how many quarters are in the jar? --so far, I have the 2X2 linear system set up as so: 15.10 = .05n + .25q 90 = .05n + .25q --is this correct? and how should I solve it, substitution or elimination? Thanks!

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90 coins in a jar of quarters and nickels. There is a total of $15.10, how many nickels and how many quarters are in the jar? --so far, I have the 2X2 linear system set up as so: 15.10 = .05n + .25q 90 = .05n + .25q --is this correct? and how should I solve it, substitution or elimination? Thanks!

Linear Algebra
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seems correct but not correct to me.
there's something wrong about it.
because u can't solve it like that, u see the coefficients are the same in front of n and q? that makes it unsolvable.

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Yes, I see that
which explains why I keep running in circles
lol. sorry, I haven't done these type of questions in ages..
that's fine, at least I have a hint on a different direction. Thank you
your welcome, let me see if I can ask others to help u.
perhaps?: 15.10 = .05n + .25q 90 = n + q since amount of quarters and nickels would be whole numbers, but money would be decimal
I believe that's it! There are 37 nickels and 53 quarters. Thanks for the nudge in the right direction. Sometimes it's the little things that help.
yeh, that's what I thought but I wasn't too sure but it should work, yeh it looks right to me.
at least I somehow helped lol.
haha, yeah, you have to know what you are doing wrong to fix it.
haha true.
but u also have to be the smart one to know where to fix it.

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