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itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0Graph the function f(x) = –x^3 + 2 Use complete sentences to explain the process of graphing f(x) = –x^3 + 2 What is the end behavior of f(x) = –x^3 + 2 ?

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1359187223800:dw

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.1we know that the graph of x^3 is

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0im so confused on this question. its rediculous... :(

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1359187389288:dw

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.1now the graph of x^3 will be

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1359187475538:dw

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.1adding 2 to the graph we get

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1359187551841:dw

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.1now form the final graph we can see the end behavior that when x approaches to +infinity f(x) approaches to infinity and when x approaches to infinity f(x) approaches to +infinity

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0okk. thankyou..can you explain in words the process of graphing? im still kind of confused even after seeing your drawings (which were excelent and clear btw, which i really appreciate)

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.1take the equation f(x)= x^3+2 put x= 0 in it we get f(0) = 0+2 = 2 we got this point (0,2) plot this point now start putting positive values (1,2,3,4,....) in x and compute f(x) now put negative values(1,2,3,4,.....) in x and compute f(x) you will get many points in this way plot all those points on a graph paper and you are done

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0thankyou soo much you have no idea how hard this is for me. i have one more question if you wouldnt mind answering it..i will post it as a new question if you are willing to give it a shot?

itsjustme_lol
 2 years ago
Best ResponseYou've already chosen the best response.0ok i will post it in a second..thank you
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