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itsjustme_lolBest ResponseYou've already chosen the best response.0
Graph the function f(x) = –x^3 + 2 Use complete sentences to explain the process of graphing f(x) = –x^3 + 2 What is the end behavior of f(x) = –x^3 + 2 ?
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
dw:1359187223800:dw
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
we know that the graph of x^3 is
 one year ago

itsjustme_lolBest ResponseYou've already chosen the best response.0
im so confused on this question. its rediculous... :(
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
dw:1359187389288:dw
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
now the graph of x^3 will be
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
dw:1359187475538:dw
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
adding 2 to the graph we get
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
dw:1359187551841:dw
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
now form the final graph we can see the end behavior that when x approaches to +infinity f(x) approaches to infinity and when x approaches to infinity f(x) approaches to +infinity
 one year ago

itsjustme_lolBest ResponseYou've already chosen the best response.0
okk. thankyou..can you explain in words the process of graphing? im still kind of confused even after seeing your drawings (which were excelent and clear btw, which i really appreciate)
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
take the equation f(x)= x^3+2 put x= 0 in it we get f(0) = 0+2 = 2 we got this point (0,2) plot this point now start putting positive values (1,2,3,4,....) in x and compute f(x) now put negative values(1,2,3,4,.....) in x and compute f(x) you will get many points in this way plot all those points on a graph paper and you are done
 one year ago

itsjustme_lolBest ResponseYou've already chosen the best response.0
thankyou soo much you have no idea how hard this is for me. i have one more question if you wouldnt mind answering it..i will post it as a new question if you are willing to give it a shot?
 one year ago

itsjustme_lolBest ResponseYou've already chosen the best response.0
ok i will post it in a second..thank you
 one year ago
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