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anonymous
 3 years ago
find sintheta
anonymous
 3 years ago
find sintheta

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shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.0Can you write this expression as : sin@ + sqrt(sec^4 a) = sec^4 a ? (@ = theta a = alpha)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the key is in the infinite.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359202205624:dw

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sec^4 \alpha = \sin\theta + \sec^3 \alpha\]Nice

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, sin(theta) =sec^4(alpha) sec^3(alpha)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359204540645:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359205220430:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how, i didn;t understand

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sin \theta = \sec^4\theta \pm \sec^2 \theta \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I guess I did a mistake

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359205684540:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359205682988:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359205748804:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x^2x+x=sec^4alpha x^2=sec^4alpha x=sec^2alpha

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if we put the value of sintheta in given equation, we get, dw:1359205875734:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x^2 =sec^4alpha x=+ sec^2 alpha

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, u r right after that putting the value of x in x^2x=sintheta

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0answer is sec^2alpha tan^2alpha
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