anonymous
  • anonymous
find sintheta
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
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shubhamsrg
  • shubhamsrg
Can you write this expression as : sin@ + sqrt(sec^4 a) = sec^4 a ? (@ = theta a = alpha)
ParthKohli
  • ParthKohli
Deja vu.

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anonymous
  • anonymous
the key is in the infinite.
anonymous
  • anonymous
|dw:1359202205624:dw|
ParthKohli
  • ParthKohli
\[\sec^4 \alpha = \sin\theta + \sec^3 \alpha\]Nice
anonymous
  • anonymous
So, sin(theta) =sec^4(alpha) -sec^3(alpha)
ParthKohli
  • ParthKohli
Nice!
anonymous
  • anonymous
|dw:1359204540645:dw|
anonymous
  • anonymous
how this came
anonymous
  • anonymous
put y = sec ^4 theta
anonymous
  • anonymous
|dw:1359205220430:dw|
anonymous
  • anonymous
how, i didn;t understand
anonymous
  • anonymous
\[\sin \theta = \sec^4\theta \pm \sec^2 \theta \]
anonymous
  • anonymous
its secθ or secalpha
anonymous
  • anonymous
I guess I did a mistake
anonymous
  • anonymous
Sorry Alpha
anonymous
  • anonymous
|dw:1359205684540:dw|
anonymous
  • anonymous
|dw:1359205682988:dw|
anonymous
  • anonymous
|dw:1359205748804:dw|
anonymous
  • anonymous
x^2-x+x=sec^4alpha x^2=sec^4alpha x=sec^2alpha
anonymous
  • anonymous
if we put the value of sintheta in given equation, we get, |dw:1359205875734:dw|
anonymous
  • anonymous
x^2 =sec^4alpha x=+- sec^2 alpha
anonymous
  • anonymous
yes, u r right after that putting the value of x in x^2-x=sintheta
anonymous
  • anonymous
yep
anonymous
  • anonymous
answer is sec^2alpha tan^2alpha

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