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shubhamsrgBest ResponseYou've already chosen the best response.0
Can you write this expression as : sin@ + sqrt(sec^4 a) = sec^4 a ? (@ = theta a = alpha)
 one year ago

ShadowysBest ResponseYou've already chosen the best response.0
the key is in the infinite.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
dw:1359202205624:dw
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
\[\sec^4 \alpha = \sin\theta + \sec^3 \alpha\]Nice
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
So, sin(theta) =sec^4(alpha) sec^3(alpha)
 one year ago

msinghBest ResponseYou've already chosen the best response.0
how, i didn;t understand
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.1
\[\sin \theta = \sec^4\theta \pm \sec^2 \theta \]
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
I guess I did a mistake
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
dw:1359205682988:dw
 one year ago

msinghBest ResponseYou've already chosen the best response.0
x^2x+x=sec^4alpha x^2=sec^4alpha x=sec^2alpha
 one year ago

msinghBest ResponseYou've already chosen the best response.0
if we put the value of sintheta in given equation, we get, dw:1359205875734:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
x^2 =sec^4alpha x=+ sec^2 alpha
 one year ago

msinghBest ResponseYou've already chosen the best response.0
yes, u r right after that putting the value of x in x^2x=sintheta
 one year ago

msinghBest ResponseYou've already chosen the best response.0
answer is sec^2alpha tan^2alpha
 one year ago
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