find sintheta

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
Can you write this expression as : sin@ + sqrt(sec^4 a) = sec^4 a ? (@ = theta a = alpha)
Deja vu.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

the key is in the infinite.
|dw:1359202205624:dw|
\[\sec^4 \alpha = \sin\theta + \sec^3 \alpha\]Nice
So, sin(theta) =sec^4(alpha) -sec^3(alpha)
Nice!
|dw:1359204540645:dw|
how this came
put y = sec ^4 theta
|dw:1359205220430:dw|
how, i didn;t understand
\[\sin \theta = \sec^4\theta \pm \sec^2 \theta \]
its secθ or secalpha
I guess I did a mistake
Sorry Alpha
|dw:1359205684540:dw|
|dw:1359205682988:dw|
|dw:1359205748804:dw|
x^2-x+x=sec^4alpha x^2=sec^4alpha x=sec^2alpha
if we put the value of sintheta in given equation, we get, |dw:1359205875734:dw|
x^2 =sec^4alpha x=+- sec^2 alpha
yes, u r right after that putting the value of x in x^2-x=sintheta
yep
answer is sec^2alpha tan^2alpha

Not the answer you are looking for?

Search for more explanations.

Ask your own question