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msingh
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shubhamsrg
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Can you write this expression as :
sin@ + sqrt(sec^4 a) = sec^4 a ?
(@ = theta
a = alpha)

ParthKohli
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Deja vu.

Shadowys
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the key is in the infinite.

sauravshakya
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dw:1359202205624:dw

ParthKohli
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\[\sec^4 \alpha = \sin\theta + \sec^3 \alpha\]Nice

sauravshakya
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So, sin(theta) =sec^4(alpha) sec^3(alpha)

ParthKohli
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Nice!

msingh
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dw:1359204540645:dw

msingh
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how this came

Yahoo!
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put y = sec ^4 theta

Yahoo!
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dw:1359205220430:dw

msingh
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how, i didn;t understand

Yahoo!
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\[\sin \theta = \sec^4\theta \pm \sec^2 \theta \]

msingh
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its secθ or secalpha

sauravshakya
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I guess I did a mistake

Yahoo!
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Sorry Alpha

msingh
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dw:1359205684540:dw

sauravshakya
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dw:1359205682988:dw

msingh
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dw:1359205748804:dw

msingh
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x^2x+x=sec^4alpha
x^2=sec^4alpha
x=sec^2alpha

msingh
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if we put the value of sintheta in given equation, we get,
dw:1359205875734:dw

sauravshakya
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x^2 =sec^4alpha
x=+ sec^2 alpha

msingh
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yes, u r right
after that putting the value of x in x^2x=sintheta

sauravshakya
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yep

msingh
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answer is sec^2alpha tan^2alpha