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shubhamsrgBest ResponseYou've already chosen the best response.0
yep, it is undefined.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
``` Prove that 0 to the 0 power is undefined. ``` Proof by contradiction. By definition, \(0^n = 0\). By definition, \(x^0 = 0\). But the two definitions contradict at \(x=0\) and \(n = 0\).
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Another one: Suppose that \(0^0 = x\). Then \(\log _ 0x = 0\). But there are infinite such values, so \(0^0\) does not exist.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
@ParthKohli x^0 =1
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
I meant to type that, sorry :(
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
x^0 = x^(nn) = x^n /x^n so it'll be undefined whenever denominator is 0.
 one year ago
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