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Yahoo!

  • 3 years ago

The tangent at a point P on the curve x^4 y^5 = a^9 meet the x and y axes in A and B respectively Then AP:PB=?

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  1. sauravshakya
    • 3 years ago
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    x^4 y^4 =a^9 d(x^4 y^4)/dx =d(a^9)/dx d(x^4)/dx *y^4 + x^4 d(y^4)/dx =0 4x^3y^4 +x^4 4y^3 dy/dx=0 dy/dx =-4x^3y^4/(4x^4y^3) dy/dx =-y/x

  2. Yahoo!
    • 3 years ago
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    Oh...No......There is a mistake in the question Sorry

  3. Yahoo!
    • 3 years ago
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    It is x^4 y^5 = a^9

  4. Yahoo!
    • 3 years ago
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    dy/dx = -4y/5x

  5. sauravshakya
    • 3 years ago
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    x^4 y^5 =a^9 d(x^4 y^5)/dx =d(a^9)/dx d(x^4)/dx *y^5 + x^4 d(y^5)/dx =0 4x^3y^5+x^4 5y^4 dy/dx=0 dy/dx =-4x^3y^5/(5x^4y^4) dy/dx =-4y/5x

  6. sauravshakya
    • 3 years ago
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    |dw:1359203248993:dw|Now, coordinate of P is

  7. sauravshakya
    • 3 years ago
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    Now, can u?

  8. Yahoo!
    • 3 years ago
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    Now Using Distance Formula Ryt ( x ,0) (0,y)

  9. sauravshakya
    • 3 years ago
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    U need to find coordinate of A and B

  10. sauravshakya
    • 3 years ago
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    First find equation of tangent

  11. Yahoo!
    • 3 years ago
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    Then we have to find x and y intercept ryt ?

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