anonymous
  • anonymous
The tangent at a point P on the curve x^4 y^5 = a^9 meet the x and y axes in A and B respectively Then AP:PB=?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
x^4 y^4 =a^9 d(x^4 y^4)/dx =d(a^9)/dx d(x^4)/dx *y^4 + x^4 d(y^4)/dx =0 4x^3y^4 +x^4 4y^3 dy/dx=0 dy/dx =-4x^3y^4/(4x^4y^3) dy/dx =-y/x
anonymous
  • anonymous
Oh...No......There is a mistake in the question Sorry
anonymous
  • anonymous
It is x^4 y^5 = a^9

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anonymous
  • anonymous
dy/dx = -4y/5x
anonymous
  • anonymous
x^4 y^5 =a^9 d(x^4 y^5)/dx =d(a^9)/dx d(x^4)/dx *y^5 + x^4 d(y^5)/dx =0 4x^3y^5+x^4 5y^4 dy/dx=0 dy/dx =-4x^3y^5/(5x^4y^4) dy/dx =-4y/5x
anonymous
  • anonymous
|dw:1359203248993:dw|Now, coordinate of P is
anonymous
  • anonymous
Now, can u?
anonymous
  • anonymous
Now Using Distance Formula Ryt ( x ,0) (0,y)
anonymous
  • anonymous
U need to find coordinate of A and B
anonymous
  • anonymous
First find equation of tangent
anonymous
  • anonymous
Then we have to find x and y intercept ryt ?

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