Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Matt71

  • 3 years ago

Find the term independent of x in the expansion of (1/2x^2-x)^9 (The answer is 10 and 1/2, just how do I get it using Binomial theorem?)

  • This Question is Closed
  1. Matt71
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    <(1/2x^2)-x>^9

  2. shubhamsrg
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    x^2 is in the denominator right ?

  3. Matt71
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    (2x2) Is

  4. Matt71
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    *(2x^2)

  5. shubhamsrg
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yep so can you tell me the rth term of this ?

  6. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy