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dy/dx =x^2/(6y)

gradient of normal is -6y/(x^2)

Nw wat to do ?

-6y/x^2 is the slope of a line which cuts of equal intercepts as x axis.

hence slope should be equal to 1 or -1.

"-6y/x^2 is the slope of a line which cuts of equal intercepts ON THE axes.

|dw:1359206768852:dw|

Did nt get u

-6y/x^2 is the slope of the normal right ?

yup

and we are given that the normal cuts of equal intercepts on the axes.

ok...then

let the Points be (a,0) and (0,a ) ryt ?

(a-0) / (0-a) = -1

What I mean is
-6y /x^2 = 1 and/or -1

ok...

we also know y = x^(3/2) /3 or -x^(3/2) /3

yes

substitute in the previous eqn to find the required value(s) of x

Yeah got it..:) thxx

glad you did. ^_^