Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Yahoo!

  • 3 years ago

The tangent at a point P on the curve x^4 y^5 = a^9 meet the x and y axes in A and B respectively Then AP:PB=?

  • This Question is Closed
  1. Yahoo!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @shubhamsrg dy/dx = -4y/5x

  2. Yahoo!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @shubhamsrg

  3. shubhamsrg
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    let it cut the axes at (a,0) and (0,b) then b/a = 4y/5x |dw:1359220445427:dw| Let the ratio be k:1 then x = a/(k+1) and y = bk/(k+1) => x/y = a/bk => k= ay/bx we know ay/bx =5/4 hence k = 5/4

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy