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Yahoo!

  • 2 years ago

The tangent at a point P on the curve x^4 y^5 = a^9 meet the x and y axes in A and B respectively Then AP:PB=?

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  1. Yahoo!
    • 2 years ago
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    @shubhamsrg dy/dx = -4y/5x

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    @shubhamsrg

  3. shubhamsrg
    • 2 years ago
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    let it cut the axes at (a,0) and (0,b) then b/a = 4y/5x |dw:1359220445427:dw| Let the ratio be k:1 then x = a/(k+1) and y = bk/(k+1) => x/y = a/bk => k= ay/bx we know ay/bx =5/4 hence k = 5/4

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