A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

marsss
 2 years ago
Best ResponseYou've already chosen the best response.3x(x^6+14x^4+16x^2+30)=0 so x=0 or x^6+14x^4+16x^2+30=0 but if x is a real number x^6+14x^4+16x^2+30>0 so it has one solution: x=0

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1One at x = 0. Factor this out and move on. If we define the LHS (with x factored out) as f(x), all coefficient signs are positive. There cannot be a positive Real Solution. No sign change if f(x), either. We are done. x = 0 is the only Real Solution. marsss identical conclusion is much simpler, but less general.

marsss
 2 years ago
Best ResponseYou've already chosen the best response.3i explained the solution of this question so it doesn't need to be general, @tkhunny

tkhunny
 2 years ago
Best ResponseYou've already chosen the best response.1@marss Absolutely agree with your comment. I just wanted the rest along for the ride. Not a complaint or criticism at all. :)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.