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thatjacksonguy Group Title

you can put a fence around a regular lot. The length of the lot must be at least 60ft. The cost of the fence along the length is $1.50 per foot. And the width is 2$ per foot. The total cost can not excede $360.

  • one year ago
  • one year ago

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  1. thatjacksonguy Group Title
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    use two variables to write a system of inequalities that models the problem what is the maximum width if the length is 60 feet?

    • one year ago
  2. thatjacksonguy Group Title
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    @Hero alittle help?

    • one year ago
  3. tomo Group Title
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    ok, so x is the length. y is the width. x = 60ft (60*1.5)+(y*2) <= 360

    • one year ago
  4. thatjacksonguy Group Title
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    ok thanx you know how the first one is done?

    • one year ago
  5. tkhunny Group Title
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    \(x \ge 60\;ft\) \((2x(1.5))+((2y)2)) \le360\) Also, this is a "regular" lot. This might mean \(x = y\). It's not as clear as I'd like it to be.

    • one year ago
  6. thatjacksonguy Group Title
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    ok there is one more so instead of the length having a limit what if the width had a limit of 36 ft? same kind you just did tomo

    • one year ago
  7. tkhunny Group Title
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    If x = y, it is the same sort of problem. Notice, however that in tomo's setup, there is only one length and one width. In mine, there are two of each. In my opinion, the unclear problem statement makes it difficult to tell which is the correct interpretation.

    • one year ago
  8. thatjacksonguy Group Title
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    you can put a fence around a regular lot. The length of the lot must be at least 60ft. The cost of the fence along the length is $1.50 per foot. And the width is 2$ per foot. The total cost can not excede $360 what is the maximum length if the width is 36ft?

    • one year ago
  9. tkhunny Group Title
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    I get it. Still just as unclear. Is a "regular" lot "square"? Is there a side or two missing? Perhaps there was a drawing?

    • one year ago
  10. thatjacksonguy Group Title
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    no drawing itz rectangle

    • one year ago
  11. tkhunny Group Title
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    Well, there you go. \(y \le 36\;ft\)

    • one year ago
  12. Outkast3r09 Group Title
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    you don't need to know whether it's a square or a rectangle the maximum length could make a square, it could maybe make a rectangle. All it asks is to maximize the length given the restriction and an equation. Tomo put it correctly. The max length would be obtained by using the most money therefore you can make it an equality. The restriction is simply a guideline it seems

    • one year ago
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