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gabie1121

  • one year ago

find the limit as x approaches 9 : WILL GIVE EQUATION IN RESPONSE

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  1. gabie1121
    • one year ago
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    \[\lim_{x \rightarrow 9}(\frac{ 1 }{ \sqrt{x}-3 } - \frac{ 6 }{ x-9 })\]

  2. AravindG
    • one year ago
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    do you know l hospital's rule?

  3. gabie1121
    • one year ago
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    please don't use lhopitals or anything im in basic calculus and haven't learned it yet. Suposed to be able to algebriaically change it to solve. I know the answer is suposed to be 1/6 i just don't know how to get there

  4. AravindG
    • one year ago
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    ok by basics , rationalise first fraction

  5. AravindG
    • one year ago
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    multiply by \(\sqrt{x}+3\) on numerator and denominator

  6. gabie1121
    • one year ago
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    so the left turns into right?

  7. gabie1121
    • one year ago
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    ugh didn't get the equation in

  8. gabie1121
    • one year ago
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    \[\frac{ \sqrt{x}+3 }{ x-3 }\]

  9. AravindG
    • one year ago
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    try again ?

  10. gabie1121
    • one year ago
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    is that not right after multiplying by \[\sqrt{x}\]+3?

  11. gabie1121
    • one year ago
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    so i now have \[\frac{ \sqrt{x}+3 }{ x-9 } - \frac{ 6 }{ x-9}\]

  12. AravindG
    • one year ago
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    ok now add them !! note denominator is same

  13. gabie1121
    • one year ago
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    well that gives me zero... and i know the answer is suposed to be 1/6

  14. AravindG
    • one year ago
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    try again?

  15. gabie1121
    • one year ago
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    right, nevermind. thanks!

  16. gabie1121
    • one year ago
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    no i still get zero

  17. gabie1121
    • one year ago
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    \[\frac{ \sqrt{x}+3 }{ x-9 }- \frac{ 6 }{ x-9 }\]

  18. AravindG
    • one year ago
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    |dw:1359220621580:dw|

  19. gabie1121
    • one year ago
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    \[\frac{ \sqrt{x}-3 }{ x-9 }\] and if i plug in 9 it will be 0 over 0

  20. AravindG
    • one year ago
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    please dont jump into putting vale ! we are not over yet!

  21. AravindG
    • one year ago
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    *value

  22. gabie1121
    • one year ago
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    ok, what do i do if i dont put the value in then

  23. gabie1121
    • one year ago
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    because your calculations give me \[\lim_{x \rightarrow 9}\frac{ \sqrt{x}-3 }{ x-9 }\]

  24. gabie1121
    • one year ago
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    do i split the bottom up? into its factors?

  25. gabie1121
    • one year ago
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    found it out! thanks!!

  26. AravindG
    • one year ago
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    yw : )

  27. RadEn
    • one year ago
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    |dw:1359220790623:dw|

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