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jabbers!

  • 3 years ago

find the distance (-1,2) (2,-4)

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  1. AravindG
    • 3 years ago
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    use distance formula

  2. RadEn
    • 3 years ago
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    use the formula : d = sqrt((y2-y1)^2 + (x2-x1)^2)

  3. AravindG
    • 3 years ago
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    \[distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\]

  4. jabbers!
    • 3 years ago
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    I don't understand how! I need help please?

  5. msingh
    • 3 years ago
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    |dw:1359221133669:dw|

  6. AravindG
    • 3 years ago
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    take (-1,2) as \((x_1,y_1) \) take (2,-4) as \((x_2,y_2) \)

  7. AravindG
    • 3 years ago
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    then use the formula above

  8. jabbers!
    • 3 years ago
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    i need to know how to solve it!! i know the formula but i need an example

  9. AravindG
    • 3 years ago
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    ok

  10. AravindG
    • 3 years ago
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    find distance between (2,4) and (5,6)

  11. RONNCC
    • 3 years ago
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    (1,2) to (3,4) distance is sqrt((3-1)^2 + (4-2)^2) = sqrt(8)

  12. RONNCC
    • 3 years ago
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    this formula comes from pythagoreas, c^2 = a^2 + b^c

  13. AravindG
    • 3 years ago
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    |dw:1359221442540:dw|

  14. AravindG
    • 3 years ago
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    |dw:1359221484203:dw|

  15. AravindG
    • 3 years ago
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    understood ?@jabbers! ?

  16. AravindG
    • 3 years ago
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    @jabbers! ?

  17. RONNCC
    • 3 years ago
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    .... sigh. sidenote. things don't come automatically to most people - you have to read them and try to understand

  18. jabbers!
    • 3 years ago
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    where did 5 come from

  19. AravindG
    • 3 years ago
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    i took second point as (5,6)

  20. jabbers!
    • 3 years ago
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    second point is (2,-4)

  21. AravindG
    • 3 years ago
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    i was doing an example!!

  22. AravindG
    • 3 years ago
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    look above !

  23. jabbers!
    • 3 years ago
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    ok.

  24. AravindG
    • 3 years ago
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    now try to do your question ! :)

  25. jabbers!
    • 3 years ago
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    |dw:1359221710963:dw|

  26. jabbers!
    • 3 years ago
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    @AravindG

  27. AravindG
    • 3 years ago
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    what did u get ?

  28. jabbers!
    • 3 years ago
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    i put it in my calculator and got an error. @AravindG

  29. jabbers!
    • 3 years ago
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    i got \[3\sqrt{5}\]

  30. AravindG
    • 3 years ago
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    you are right !!

  31. jabbers!
    • 3 years ago
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    thank u. finally!

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