jabbers!
find the distance (1,2) (2,4)



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AravindG
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use distance formula

RadEn
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use the formula :
d = sqrt((y2y1)^2 + (x2x1)^2)

AravindG
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\[distance=\sqrt{(x_2x_1)^2+(y_2y_1)^2}\]

jabbers!
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I don't understand how! I need help please?

msingh
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dw:1359221133669:dw

AravindG
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take (1,2) as \((x_1,y_1) \)
take (2,4) as \((x_2,y_2) \)

AravindG
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then use the formula above

jabbers!
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i need to know how to solve it!! i know the formula but i need an example

AravindG
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ok

AravindG
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find distance between (2,4) and (5,6)

RONNCC
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(1,2) to (3,4) distance is sqrt((31)^2 + (42)^2) = sqrt(8)

RONNCC
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this formula comes from pythagoreas, c^2 = a^2 + b^c

AravindG
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dw:1359221442540:dw

AravindG
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dw:1359221484203:dw

AravindG
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understood ?@jabbers! ?

AravindG
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@jabbers! ?

RONNCC
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.... sigh. sidenote. things don't come automatically to most people  you have to read them and try to understand

jabbers!
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where did 5 come from

AravindG
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i took second point as (5,6)

jabbers!
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second point is (2,4)

AravindG
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i was doing an example!!

AravindG
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look above !

jabbers!
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ok.

AravindG
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now try to do your question ! :)

jabbers!
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dw:1359221710963:dw

jabbers!
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@AravindG

AravindG
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what did u get ?

jabbers!
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i put it in my calculator and got an error. @AravindG

jabbers!
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i got \[3\sqrt{5}\]

AravindG
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you are right !!

jabbers!
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thank u. finally!