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anonymous
 3 years ago
Determine the zeros of f(x) = x3  12x2 + 28x  9.
anonymous
 3 years ago
Determine the zeros of f(x) = x3  12x2 + 28x  9.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, I'd remove the x^2 from the first two terms, making it x^2 (x  12 + 28x  9)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and then combine like terms, making it x^2 (29x  21)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0... you can't just remove x^2 from the front. what about the back? you get x^2(x  12) + 28x  9

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0start by hit and tril, put x=1, 1, 2, 2 till u get f(x)=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359226096145:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359226195996:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0try ur self till u get f(x)=0 after that v proceed next

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let "a" is that value ie f(a)=0 means "a" is a root and xa is a factor, now divide the original equation by xa to get another factor(that will b quadratic, factorize that and equate the three factors one by one to get the roots,

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0my laptop battery is low , m about to offline if i didnt reach power on time, good luck for the question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I couldn't find any numbers that made f(x)=0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok sigh i don't know what he was doing

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but via factoring you get (x9)(x^23x+1)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0therefore x = 9 and you use the quadratic formula to find the roots for x^2  3x + 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm having trouble using the quadratic formula with (x^2  3x + 1)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[a=1,b=3,c=1\] \[x=\frac{b\pm\sqrt{b^24ac}}{2a}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, a=1, b=3, and c=1?
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