Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Determine the zeros of f(x) = x3 - 12x2 + 28x - 9.

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
try factoring :)
so, I'd remove the x^2 from the first two terms, making it x^2 (x - 12 + 28x - 9)?
and then combine like terms, making it x^2 (29x - 21)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

... you can't just remove x^2 from the front. what about the back? you get x^2(x - 12) + 28x - 9
start by hit and tril, put x=1, -1, 2, -2 till u get f(x)=0
ok
|dw:1359226096145:dw|
|dw:1359226195996:dw|
try ur self till u get f(x)=0 after that v proceed next
ok
let "a" is that value i-e f(a)=0 means "a" is a root and x-a is a factor, now divide the original equation by x-a to get another factor(that will b quadratic, factorize that and equate the three factors one by one to get the roots,
my laptop battery is low , m about to offline if i didnt reach power on time, good luck for the question
I couldn't find any numbers that made f(x)=0
ok sigh i don't know what he was doing
but via factoring you get (x-9)(x^2-3x+1)
therefore x = 9 and you use the quadratic formula to find the roots for x^2 - 3x + 1
I'm having trouble using the quadratic formula with (x^2 - 3x + 1)
\[a=1,b=-3,c=1\] \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
so, a=1, b=-3, and c=1?

Not the answer you are looking for?

Search for more explanations.

Ask your own question