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Hey, please help:)

Mathematics
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\[3 \sqrt[3]{24}\]
Hint:\[\sqrt[3]{24}=\sqrt[3]{8\cdot3}=\sqrt[3]8\cdot\sqrt[3]{3}\]
Thank you!

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Other answers:

Can you write the answer?
\[6\sqrt[3]{3}\]
Very nice.
Could you help me with another question?
\[3\sqrt{x+4}-2=13\]
What is the problem?
What cant you do?
Solve for \(\sqrt{x+4}\).
Hey! Are you here?
Yes, I am sorry
couldn't I just do 4-2 giving me 2 so then I do x+2=13?
x+2=13 -2 -2 x=11
idk
Can you solve \(3y-2=13\) ?
y=5
Yes. Think if \(y=\sqrt{x+4}\).
If you make a substitution \(y=\sqrt{x+4}\), you will get \(\sqrt{x+4}=5\). Do you know what \(\sqrt{\phantom{a}}\) sign means?
square root
What does square root means?
a number multiplied by itself?
Can you tell me what does \(\sqrt{16}\) mean?
4?
Yes. But Also -4 too. -4*(-4)=16. So what can you say about \(\sqrt{x+4}=5\) ?
x=1?
I don't think I know
See the analogy. Try to think. Compute \(\sqrt{36}, \sqrt{25}, \sqrt{\frac14}\).
alright. 6,5,2
Check the last one.
\(\sqrt x\) is the inverse function for \(x^2\). \(\sqrt x\) is a number that squared must be \(x\). \((\sqrt x )^2=x\). Think about last one.
I still think it's1
Compute \(\sqrt{\frac14}\).
2
\(2^2\neq\frac14\)
Try again.
1/4
\(\left(\frac14\right)^2\neq\frac14\). Try again.
So I have to square it?
You have to find \(\sqrt{\frac14}\) using the definition I wrote above.
.5
.5*.5=1/4
Yes. Thats it. Now back to \(\sqrt{x+4}=5\). Can you solve it?
Would I plug something in x?
Ok. Can you solve this: \(\sqrt x = 2\) ?
4
Yes. Thats it. Now back to \(\sqrt{x+4}=5\). Can you solve it?
25?
\(\sqrt{25+4}\neq5\)
21
Bingo. You solved this by your own. Congratulations!
It has to be that's why thought of 25 =5
Thank you:)!!
You are welcome.

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