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jackoo

  • one year ago

Hey, please help:)

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  1. jackoo
    • one year ago
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    \[3 \sqrt[3]{24}\]

  2. klimenkov
    • one year ago
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    Hint:\[\sqrt[3]{24}=\sqrt[3]{8\cdot3}=\sqrt[3]8\cdot\sqrt[3]{3}\]

  3. jackoo
    • one year ago
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    Thank you!

  4. klimenkov
    • one year ago
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    Can you write the answer?

  5. jackoo
    • one year ago
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    \[6\sqrt[3]{3}\]

  6. klimenkov
    • one year ago
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    Very nice.

  7. jackoo
    • one year ago
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    Could you help me with another question?

  8. jackoo
    • one year ago
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    \[3\sqrt{x+4}-2=13\]

  9. klimenkov
    • one year ago
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    What is the problem?

  10. klimenkov
    • one year ago
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    What cant you do?

  11. klimenkov
    • one year ago
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    Solve for \(\sqrt{x+4}\).

  12. klimenkov
    • one year ago
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    Hey! Are you here?

  13. jackoo
    • one year ago
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    Yes, I am sorry

  14. jackoo
    • one year ago
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    couldn't I just do 4-2 giving me 2 so then I do x+2=13?

  15. jackoo
    • one year ago
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    x+2=13 -2 -2 x=11

  16. jackoo
    • one year ago
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    idk

  17. klimenkov
    • one year ago
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    Can you solve \(3y-2=13\) ?

  18. jackoo
    • one year ago
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    y=5

  19. klimenkov
    • one year ago
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    Yes. Think if \(y=\sqrt{x+4}\).

  20. klimenkov
    • one year ago
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    If you make a substitution \(y=\sqrt{x+4}\), you will get \(\sqrt{x+4}=5\). Do you know what \(\sqrt{\phantom{a}}\) sign means?

  21. jackoo
    • one year ago
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    square root

  22. klimenkov
    • one year ago
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    What does square root means?

  23. jackoo
    • one year ago
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    a number multiplied by itself?

  24. klimenkov
    • one year ago
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    Can you tell me what does \(\sqrt{16}\) mean?

  25. jackoo
    • one year ago
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    4?

  26. klimenkov
    • one year ago
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    Yes. But Also -4 too. -4*(-4)=16. So what can you say about \(\sqrt{x+4}=5\) ?

  27. jackoo
    • one year ago
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    x=1?

  28. jackoo
    • one year ago
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    I don't think I know

  29. klimenkov
    • one year ago
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    See the analogy. Try to think. Compute \(\sqrt{36}, \sqrt{25}, \sqrt{\frac14}\).

  30. jackoo
    • one year ago
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    alright. 6,5,2

  31. klimenkov
    • one year ago
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    Check the last one.

  32. klimenkov
    • one year ago
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    \(\sqrt x\) is the inverse function for \(x^2\). \(\sqrt x\) is a number that squared must be \(x\). \((\sqrt x )^2=x\). Think about last one.

  33. jackoo
    • one year ago
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    I still think it's1

  34. klimenkov
    • one year ago
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    Compute \(\sqrt{\frac14}\).

  35. jackoo
    • one year ago
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    2

  36. klimenkov
    • one year ago
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    \(2^2\neq\frac14\)

  37. klimenkov
    • one year ago
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    Try again.

  38. jackoo
    • one year ago
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    1/4

  39. klimenkov
    • one year ago
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    \(\left(\frac14\right)^2\neq\frac14\). Try again.

  40. jackoo
    • one year ago
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    So I have to square it?

  41. klimenkov
    • one year ago
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    You have to find \(\sqrt{\frac14}\) using the definition I wrote above.

  42. jackoo
    • one year ago
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    .5

  43. jackoo
    • one year ago
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    .5*.5=1/4

  44. klimenkov
    • one year ago
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    Yes. Thats it. Now back to \(\sqrt{x+4}=5\). Can you solve it?

  45. jackoo
    • one year ago
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    Would I plug something in x?

  46. klimenkov
    • one year ago
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    Ok. Can you solve this: \(\sqrt x = 2\) ?

  47. jackoo
    • one year ago
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    4

  48. klimenkov
    • one year ago
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    Yes. Thats it. Now back to \(\sqrt{x+4}=5\). Can you solve it?

  49. jackoo
    • one year ago
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    25?

  50. klimenkov
    • one year ago
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    \(\sqrt{25+4}\neq5\)

  51. jackoo
    • one year ago
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    21

  52. klimenkov
    • one year ago
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    Bingo. You solved this by your own. Congratulations!

  53. jackoo
    • one year ago
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    It has to be that's why thought of 25 =5

  54. jackoo
    • one year ago
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    Thank you:)!!

  55. klimenkov
    • one year ago
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    You are welcome.

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