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Do you know the relationships of the sides in a 30-60-90 triangle?

i havect done a 30 degree one

i had only done 45-90-45 i understand thoese

|dw:1359235775166:dw|

Try that. It will work.

dont i devide the hypotnuse by sqrt 3?

What is the side opposite the 30 degree angle in your problem?

1?

|dw:1359236251126:dw|

What is the side opposite the 30 degree angle?

ohh duh 9

Now, multiply the side opposite the 30 degree angle by two and that will the hypotenuse.

x=9sqrt 3

What does it mean to multiply by 2?

|dw:1359236599337:dw|

so x= 18 right

wow tht was easy i was over thinking it XD

yes. And if you had to find the other leg, it would be 9 multiplied by sqrt 3

\[9\sqrt{3}\]

like that will be 16sqrt 3

|dw:1359237264725:dw|

What is the side opposite the 30 degree angle labelled?

What is the hypotenuse?

16

The side opposite the 30 degree angle is 1/2 the hypotenuse. So what is y?

And the other leg is the short leg multiplied by sqrt 3 so what is the other leg?

8sqrt3

Perfect!!

yas thx ur really good tutor

ty

ohh yeah how can u do this

|dw:1359237668453:dw|

symplify

Rationalize the denominator by multipling by sqrt2 over sqrt2

\[\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}} \]

10sqrt 2 is left

In the numerator, yes. What about the denominator?

sqrt4

Which is?

and then 2 and devide and i get 5 sqrt2

Yes. that is correct.

There is one important thing I would like for you to learn.

ok

The operation "taking sqrt" is the inverse of the operation "squaring".

ohh like powers 4^2=16

So when you see something like:
\[\sqrt{2}\times \sqrt{2}\]

You should think:
\[(\sqrt{2})^2\]

And you should think: those two operations "undo" each other so the result is 2

ohh i see i get it thx

yw