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Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Do you know the relationships of the sides in a 306090 triangle?
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
i havect done a 30 degree one
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
i had only done 459045 i understand thoese
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
dw:1359235775166:dw
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Try that. It will work.
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
dont i devide the hypotnuse by sqrt 3?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
What is the side opposite the 30 degree angle in your problem?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
dw:1359236251126:dw
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
What is the side opposite the 30 degree angle?
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
ohh duh 9
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Now, multiply the side opposite the 30 degree angle by two and that will the hypotenuse.
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
x=9sqrt 3
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
What does it mean to multiply by 2?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
dw:1359236599337:dw
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
so x= 18 right
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
wow tht was easy i was over thinking it XD
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
yes. And if you had to find the other leg, it would be 9 multiplied by sqrt 3
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
\[9\sqrt{3}\]
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
like that will be 16sqrt 3
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
dw:1359237264725:dw
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
What is the side opposite the 30 degree angle labelled?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
What is the hypotenuse?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
The side opposite the 30 degree angle is 1/2 the hypotenuse. So what is y?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
And the other leg is the short leg multiplied by sqrt 3 so what is the other leg?
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
yas thx ur really good tutor
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
ohh yeah how can u do this
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
dw:1359237668453:dw
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
symplify
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Rationalize the denominator by multipling by sqrt2 over sqrt2
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
\[\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}} \]
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
10sqrt 2 is left
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
In the numerator, yes. What about the denominator?
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
and then 2 and devide and i get 5 sqrt2
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
Yes. that is correct.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
There is one important thing I would like for you to learn.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
The operation "taking sqrt" is the inverse of the operation "squaring".
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
ohh like powers 4^2=16
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
So when you see something like: \[\sqrt{2}\times \sqrt{2}\]
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
You should think: \[(\sqrt{2})^2\]
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
And you should think: those two operations "undo" each other so the result is 2
 one year ago

Reaper534 Group TitleBest ResponseYou've already chosen the best response.0
ohh i see i get it thx
 one year ago
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