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Reaper534

  • 2 years ago

find x

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  1. Mertsj
    • 2 years ago
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    Do you know the relationships of the sides in a 30-60-90 triangle?

  2. Reaper534
    • 2 years ago
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    i havect done a 30 degree one

  3. Reaper534
    • 2 years ago
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    i had only done 45-90-45 i understand thoese

  4. Mertsj
    • 2 years ago
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    |dw:1359235775166:dw|

  5. Mertsj
    • 2 years ago
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    Try that. It will work.

  6. Reaper534
    • 2 years ago
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    dont i devide the hypotnuse by sqrt 3?

  7. Reaper534
    • 2 years ago
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    @Hero

  8. Mertsj
    • 2 years ago
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    What is the side opposite the 30 degree angle in your problem?

  9. Reaper534
    • 2 years ago
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    1?

  10. Mertsj
    • 2 years ago
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    |dw:1359236251126:dw|

  11. Mertsj
    • 2 years ago
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    What is the side opposite the 30 degree angle?

  12. Reaper534
    • 2 years ago
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    ohh duh 9

  13. Mertsj
    • 2 years ago
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    Now, multiply the side opposite the 30 degree angle by two and that will the hypotenuse.

  14. Reaper534
    • 2 years ago
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    x=9sqrt 3

  15. Mertsj
    • 2 years ago
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    What does it mean to multiply by 2?

  16. Mertsj
    • 2 years ago
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    |dw:1359236599337:dw|

  17. Reaper534
    • 2 years ago
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    so x= 18 right

  18. Reaper534
    • 2 years ago
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    wow tht was easy i was over thinking it XD

  19. Mertsj
    • 2 years ago
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    yes. And if you had to find the other leg, it would be 9 multiplied by sqrt 3

  20. Mertsj
    • 2 years ago
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    \[9\sqrt{3}\]

  21. Reaper534
    • 2 years ago
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    like that will be 16sqrt 3

  22. Mertsj
    • 2 years ago
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    |dw:1359237264725:dw|

  23. Mertsj
    • 2 years ago
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    What is the side opposite the 30 degree angle labelled?

  24. Reaper534
    • 2 years ago
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    y

  25. Mertsj
    • 2 years ago
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    What is the hypotenuse?

  26. Reaper534
    • 2 years ago
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    16

  27. Mertsj
    • 2 years ago
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    The side opposite the 30 degree angle is 1/2 the hypotenuse. So what is y?

  28. Reaper534
    • 2 years ago
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    8

  29. Mertsj
    • 2 years ago
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    And the other leg is the short leg multiplied by sqrt 3 so what is the other leg?

  30. Reaper534
    • 2 years ago
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    8sqrt3

  31. Mertsj
    • 2 years ago
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    Perfect!!

  32. Reaper534
    • 2 years ago
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    yas thx ur really good tutor

  33. Mertsj
    • 2 years ago
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    ty

  34. Reaper534
    • 2 years ago
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    ohh yeah how can u do this

  35. Reaper534
    • 2 years ago
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    |dw:1359237668453:dw|

  36. Reaper534
    • 2 years ago
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    symplify

  37. Mertsj
    • 2 years ago
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    Rationalize the denominator by multipling by sqrt2 over sqrt2

  38. Mertsj
    • 2 years ago
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    \[\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}} \]

  39. Reaper534
    • 2 years ago
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    10sqrt 2 is left

  40. Mertsj
    • 2 years ago
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    In the numerator, yes. What about the denominator?

  41. Reaper534
    • 2 years ago
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    sqrt4

  42. Mertsj
    • 2 years ago
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    Which is?

  43. Reaper534
    • 2 years ago
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    and then 2 and devide and i get 5 sqrt2

  44. Mertsj
    • 2 years ago
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    Yes. that is correct.

  45. Mertsj
    • 2 years ago
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    There is one important thing I would like for you to learn.

  46. Reaper534
    • 2 years ago
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    ok

  47. Mertsj
    • 2 years ago
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    The operation "taking sqrt" is the inverse of the operation "squaring".

  48. Reaper534
    • 2 years ago
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    ohh like powers 4^2=16

  49. Mertsj
    • 2 years ago
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    So when you see something like: \[\sqrt{2}\times \sqrt{2}\]

  50. Mertsj
    • 2 years ago
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    You should think: \[(\sqrt{2})^2\]

  51. Mertsj
    • 2 years ago
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    And you should think: those two operations "undo" each other so the result is 2

  52. Reaper534
    • 2 years ago
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    ohh i see i get it thx

  53. Mertsj
    • 2 years ago
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    yw

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