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anonymous
 3 years ago
find x
anonymous
 3 years ago
find x

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Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2Do you know the relationships of the sides in a 306090 triangle?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i havect done a 30 degree one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i had only done 459045 i understand thoese

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dont i devide the hypotnuse by sqrt 3?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2What is the side opposite the 30 degree angle in your problem?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2What is the side opposite the 30 degree angle?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2Now, multiply the side opposite the 30 degree angle by two and that will the hypotenuse.

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2What does it mean to multiply by 2?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wow tht was easy i was over thinking it XD

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2yes. And if you had to find the other leg, it would be 9 multiplied by sqrt 3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0like that will be 16sqrt 3

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2What is the side opposite the 30 degree angle labelled?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2The side opposite the 30 degree angle is 1/2 the hypotenuse. So what is y?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2And the other leg is the short leg multiplied by sqrt 3 so what is the other leg?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yas thx ur really good tutor

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh yeah how can u do this

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359237668453:dw

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2Rationalize the denominator by multipling by sqrt2 over sqrt2

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}} \]

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2In the numerator, yes. What about the denominator?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and then 2 and devide and i get 5 sqrt2

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2There is one important thing I would like for you to learn.

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2The operation "taking sqrt" is the inverse of the operation "squaring".

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh like powers 4^2=16

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2So when you see something like: \[\sqrt{2}\times \sqrt{2}\]

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2You should think: \[(\sqrt{2})^2\]

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.2And you should think: those two operations "undo" each other so the result is 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohh i see i get it thx
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