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http://roads.advancedacademics.com/contentserver/content/roadssection/279450/questions/assessments/t-righttrianglespythagoreantheoremquiz/geometry_4.3_quiz_10q.gif
Do you know the relationships of the sides in a 30-60-90 triangle?
i havect done a 30 degree one

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Other answers:

i had only done 45-90-45 i understand thoese
|dw:1359235775166:dw|
Try that. It will work.
dont i devide the hypotnuse by sqrt 3?
What is the side opposite the 30 degree angle in your problem?
1?
|dw:1359236251126:dw|
What is the side opposite the 30 degree angle?
ohh duh 9
Now, multiply the side opposite the 30 degree angle by two and that will the hypotenuse.
x=9sqrt 3
What does it mean to multiply by 2?
|dw:1359236599337:dw|
so x= 18 right
wow tht was easy i was over thinking it XD
yes. And if you had to find the other leg, it would be 9 multiplied by sqrt 3
\[9\sqrt{3}\]
http://roads.advancedacademics.com/contentserver/content/roadssection/279450/questions/assessments/t-righttrianglespythagoreantheoremquiz/geometry_4.3_quiz_12q.gif
like that will be 16sqrt 3
|dw:1359237264725:dw|
What is the side opposite the 30 degree angle labelled?
y
What is the hypotenuse?
16
The side opposite the 30 degree angle is 1/2 the hypotenuse. So what is y?
8
And the other leg is the short leg multiplied by sqrt 3 so what is the other leg?
8sqrt3
Perfect!!
yas thx ur really good tutor
ty
ohh yeah how can u do this
|dw:1359237668453:dw|
symplify
Rationalize the denominator by multipling by sqrt2 over sqrt2
\[\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}} \]
10sqrt 2 is left
In the numerator, yes. What about the denominator?
sqrt4
Which is?
and then 2 and devide and i get 5 sqrt2
Yes. that is correct.
There is one important thing I would like for you to learn.
ok
The operation "taking sqrt" is the inverse of the operation "squaring".
ohh like powers 4^2=16
So when you see something like: \[\sqrt{2}\times \sqrt{2}\]
You should think: \[(\sqrt{2})^2\]
And you should think: those two operations "undo" each other so the result is 2
ohh i see i get it thx
yw

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