anonymous
  • anonymous
find x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
http://roads.advancedacademics.com/contentserver/content/roadssection/279450/questions/assessments/t-righttrianglespythagoreantheoremquiz/geometry_4.3_quiz_10q.gif
Mertsj
  • Mertsj
Do you know the relationships of the sides in a 30-60-90 triangle?
anonymous
  • anonymous
i havect done a 30 degree one

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anonymous
  • anonymous
i had only done 45-90-45 i understand thoese
Mertsj
  • Mertsj
|dw:1359235775166:dw|
Mertsj
  • Mertsj
Try that. It will work.
anonymous
  • anonymous
dont i devide the hypotnuse by sqrt 3?
anonymous
  • anonymous
@Hero
Mertsj
  • Mertsj
What is the side opposite the 30 degree angle in your problem?
anonymous
  • anonymous
1?
Mertsj
  • Mertsj
|dw:1359236251126:dw|
Mertsj
  • Mertsj
What is the side opposite the 30 degree angle?
anonymous
  • anonymous
ohh duh 9
Mertsj
  • Mertsj
Now, multiply the side opposite the 30 degree angle by two and that will the hypotenuse.
anonymous
  • anonymous
x=9sqrt 3
Mertsj
  • Mertsj
What does it mean to multiply by 2?
Mertsj
  • Mertsj
|dw:1359236599337:dw|
anonymous
  • anonymous
so x= 18 right
anonymous
  • anonymous
wow tht was easy i was over thinking it XD
Mertsj
  • Mertsj
yes. And if you had to find the other leg, it would be 9 multiplied by sqrt 3
Mertsj
  • Mertsj
\[9\sqrt{3}\]
anonymous
  • anonymous
http://roads.advancedacademics.com/contentserver/content/roadssection/279450/questions/assessments/t-righttrianglespythagoreantheoremquiz/geometry_4.3_quiz_12q.gif
anonymous
  • anonymous
like that will be 16sqrt 3
Mertsj
  • Mertsj
|dw:1359237264725:dw|
Mertsj
  • Mertsj
What is the side opposite the 30 degree angle labelled?
anonymous
  • anonymous
y
Mertsj
  • Mertsj
What is the hypotenuse?
anonymous
  • anonymous
16
Mertsj
  • Mertsj
The side opposite the 30 degree angle is 1/2 the hypotenuse. So what is y?
anonymous
  • anonymous
8
Mertsj
  • Mertsj
And the other leg is the short leg multiplied by sqrt 3 so what is the other leg?
anonymous
  • anonymous
8sqrt3
Mertsj
  • Mertsj
Perfect!!
anonymous
  • anonymous
yas thx ur really good tutor
Mertsj
  • Mertsj
ty
anonymous
  • anonymous
ohh yeah how can u do this
anonymous
  • anonymous
|dw:1359237668453:dw|
anonymous
  • anonymous
symplify
Mertsj
  • Mertsj
Rationalize the denominator by multipling by sqrt2 over sqrt2
Mertsj
  • Mertsj
\[\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}} \]
anonymous
  • anonymous
10sqrt 2 is left
Mertsj
  • Mertsj
In the numerator, yes. What about the denominator?
anonymous
  • anonymous
sqrt4
Mertsj
  • Mertsj
Which is?
anonymous
  • anonymous
and then 2 and devide and i get 5 sqrt2
Mertsj
  • Mertsj
Yes. that is correct.
Mertsj
  • Mertsj
There is one important thing I would like for you to learn.
anonymous
  • anonymous
ok
Mertsj
  • Mertsj
The operation "taking sqrt" is the inverse of the operation "squaring".
anonymous
  • anonymous
ohh like powers 4^2=16
Mertsj
  • Mertsj
So when you see something like: \[\sqrt{2}\times \sqrt{2}\]
Mertsj
  • Mertsj
You should think: \[(\sqrt{2})^2\]
Mertsj
  • Mertsj
And you should think: those two operations "undo" each other so the result is 2
anonymous
  • anonymous
ohh i see i get it thx
Mertsj
  • Mertsj
yw

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