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Reaper534 Group Title

find x

  • one year ago
  • one year ago

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  1. Mertsj Group Title
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    Do you know the relationships of the sides in a 30-60-90 triangle?

    • one year ago
  2. Reaper534 Group Title
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    i havect done a 30 degree one

    • one year ago
  3. Reaper534 Group Title
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    i had only done 45-90-45 i understand thoese

    • one year ago
  4. Mertsj Group Title
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    |dw:1359235775166:dw|

    • one year ago
  5. Mertsj Group Title
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    Try that. It will work.

    • one year ago
  6. Reaper534 Group Title
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    dont i devide the hypotnuse by sqrt 3?

    • one year ago
  7. Reaper534 Group Title
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    @Hero

    • one year ago
  8. Mertsj Group Title
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    What is the side opposite the 30 degree angle in your problem?

    • one year ago
  9. Reaper534 Group Title
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    1?

    • one year ago
  10. Mertsj Group Title
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    |dw:1359236251126:dw|

    • one year ago
  11. Mertsj Group Title
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    What is the side opposite the 30 degree angle?

    • one year ago
  12. Reaper534 Group Title
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    ohh duh 9

    • one year ago
  13. Mertsj Group Title
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    Now, multiply the side opposite the 30 degree angle by two and that will the hypotenuse.

    • one year ago
  14. Reaper534 Group Title
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    x=9sqrt 3

    • one year ago
  15. Mertsj Group Title
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    What does it mean to multiply by 2?

    • one year ago
  16. Mertsj Group Title
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    |dw:1359236599337:dw|

    • one year ago
  17. Reaper534 Group Title
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    so x= 18 right

    • one year ago
  18. Reaper534 Group Title
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    wow tht was easy i was over thinking it XD

    • one year ago
  19. Mertsj Group Title
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    yes. And if you had to find the other leg, it would be 9 multiplied by sqrt 3

    • one year ago
  20. Mertsj Group Title
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    \[9\sqrt{3}\]

    • one year ago
  21. Reaper534 Group Title
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    like that will be 16sqrt 3

    • one year ago
  22. Mertsj Group Title
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    |dw:1359237264725:dw|

    • one year ago
  23. Mertsj Group Title
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    What is the side opposite the 30 degree angle labelled?

    • one year ago
  24. Reaper534 Group Title
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    y

    • one year ago
  25. Mertsj Group Title
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    What is the hypotenuse?

    • one year ago
  26. Reaper534 Group Title
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    16

    • one year ago
  27. Mertsj Group Title
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    The side opposite the 30 degree angle is 1/2 the hypotenuse. So what is y?

    • one year ago
  28. Reaper534 Group Title
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    8

    • one year ago
  29. Mertsj Group Title
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    And the other leg is the short leg multiplied by sqrt 3 so what is the other leg?

    • one year ago
  30. Reaper534 Group Title
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    8sqrt3

    • one year ago
  31. Mertsj Group Title
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    Perfect!!

    • one year ago
  32. Reaper534 Group Title
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    yas thx ur really good tutor

    • one year ago
  33. Mertsj Group Title
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    ty

    • one year ago
  34. Reaper534 Group Title
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    ohh yeah how can u do this

    • one year ago
  35. Reaper534 Group Title
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    |dw:1359237668453:dw|

    • one year ago
  36. Reaper534 Group Title
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    symplify

    • one year ago
  37. Mertsj Group Title
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    Rationalize the denominator by multipling by sqrt2 over sqrt2

    • one year ago
  38. Mertsj Group Title
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    \[\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}} \]

    • one year ago
  39. Reaper534 Group Title
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    10sqrt 2 is left

    • one year ago
  40. Mertsj Group Title
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    In the numerator, yes. What about the denominator?

    • one year ago
  41. Reaper534 Group Title
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    sqrt4

    • one year ago
  42. Mertsj Group Title
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    Which is?

    • one year ago
  43. Reaper534 Group Title
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    and then 2 and devide and i get 5 sqrt2

    • one year ago
  44. Mertsj Group Title
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    Yes. that is correct.

    • one year ago
  45. Mertsj Group Title
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    There is one important thing I would like for you to learn.

    • one year ago
  46. Reaper534 Group Title
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    ok

    • one year ago
  47. Mertsj Group Title
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    The operation "taking sqrt" is the inverse of the operation "squaring".

    • one year ago
  48. Reaper534 Group Title
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    ohh like powers 4^2=16

    • one year ago
  49. Mertsj Group Title
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    So when you see something like: \[\sqrt{2}\times \sqrt{2}\]

    • one year ago
  50. Mertsj Group Title
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    You should think: \[(\sqrt{2})^2\]

    • one year ago
  51. Mertsj Group Title
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    And you should think: those two operations "undo" each other so the result is 2

    • one year ago
  52. Reaper534 Group Title
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    ohh i see i get it thx

    • one year ago
  53. Mertsj Group Title
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    yw

    • one year ago
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