anonymous
  • anonymous
y varies jointly as x and z, and y = 32 m, x = 6 m, and z = 8 m. What is the value of y when x = 5 m and z = 12 m?
Mathematics
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SOLVED
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schrodinger
  • schrodinger
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Mertsj
  • Mertsj
Can you write the joint variation equation for x y and z? Use k for the constant.
anonymous
  • anonymous
@jim_thompson5910
Mertsj
  • Mertsj
y=kxz

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Mertsj
  • Mertsj
Now plug in the given values and find k.
jim_thompson5910
  • jim_thompson5910
does Mertsj's response make sense?
anonymous
  • anonymous
a little, im still a little confused ..
anonymous
  • anonymous
so it would be 32m= k *5m*12m
jim_thompson5910
  • jim_thompson5910
y = kxz we're given y = 32 m, x = 6 m, and z = 8 m plug all this in to get 32 = k*6*8 now solve for k Note: I think we can ignore the m's because I think they refer to meters (eg: x = 6 m means x is 6 meters long)
anonymous
  • anonymous
4?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
32 = k*6*8 32 = k*48 k = ??
anonymous
  • anonymous
its 4?
jim_thompson5910
  • jim_thompson5910
no it's not 4 divide both sides by 48 to solve for k
anonymous
  • anonymous
0.6?
jim_thompson5910
  • jim_thompson5910
more like 0.667 but I would keep it as a fraction so k = 2/3
jim_thompson5910
  • jim_thompson5910
y = kxz y = (2/3)xz y = (2/3)*5*12 plug in x = 5 and z = 12 y = ???
anonymous
  • anonymous
my choices are 90m, 4m, 40m, 9m
jim_thompson5910
  • jim_thompson5910
5*12 is what
anonymous
  • anonymous
60
jim_thompson5910
  • jim_thompson5910
now multiply that by 2 then divide that result by 3
anonymous
  • anonymous
4
jim_thompson5910
  • jim_thompson5910
close, but not quite
anonymous
  • anonymous
40*
jim_thompson5910
  • jim_thompson5910
yep
anonymous
  • anonymous
thank you(:
jim_thompson5910
  • jim_thompson5910
you're welcome

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