y varies jointly as x and z, and y = 32 m, x = 6 m, and z = 8 m.
What is the value of y when x = 5 m and z = 12 m?
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Can you write the joint variation equation for x y and z? Use k for the constant.
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Now plug in the given values and find k.
does Mertsj's response make sense?
a little, im still a little confused ..
so it would be 32m= k *5m*12m
y = kxz
we're given y = 32 m, x = 6 m, and z = 8 m
plug all this in to get
32 = k*6*8
now solve for k
Note: I think we can ignore the m's because I think they refer to meters (eg: x = 6 m means x is 6 meters long)
32 = k*6*8
32 = k*48
k = ??
no it's not 4
divide both sides by 48 to solve for k
more like 0.667
but I would keep it as a fraction so k = 2/3
y = kxz
y = (2/3)xz
y = (2/3)*5*12 plug in x = 5 and z = 12
y = ???
my choices are 90m, 4m, 40m, 9m
5*12 is what
now multiply that by 2
then divide that result by 3