A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.2\(\vec{F}(x,y,z)=y\cdot\vec{k}\)

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.2dw:1359238654831:dw

Wislar
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure what you did there?

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure what she did there either.

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.2This field doesn't depent on \(x\) and \(z\). That means that there will be the same vectors in the planes \(y=\text{const}\). \(\vec{k}\) is a vector that has length = 1 and is collinear to \(z\)axis. I drew 3 planes \(y=\text{const}\) for different values of this constant.

Wislar
 one year ago
Best ResponseYou've already chosen the best response.0So, say (1,0,0).. it would be the zero vector, so wouldn't it just be a point and not a line of length 1?

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.2A vector field is a vector function. Its argument is a vector (point) and its value is also a vector. For example if you take a point (1,0,0), thats mean that \(x=1,y=z=0.\). So, \(\vec{F}(1,0,0)=0\cdot\vec{k}=\vec{0}\). For every vector that has ycoordinate = 0, it will be zero vector. y=0 is a plane. Every vector in this plane will be zerovector. If you take (0,1,0), then \(\vec{F}(0,1,0)=1\cdot\vec{k}=\vec{k}\). Every vector in the plane y=1 will be \(\vec{k}\). And so on.

Wislar
 one year ago
Best ResponseYou've already chosen the best response.0I get it!! Thank you so much! So everything with a negative y value would be going up and everything with a positive y value would be going down?

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.2Yes. Sorry, my fault. I have lost the "" sign. I'm happy that you've got it. You are welcome.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.