## KrystaRenee What is the value of 2x^-2y^-2 for x = 3 and y = -2? 1/18 72 2(-6)^-4 1/648 one year ago one year ago

1. Mertsj

just replace each x with 3 and each y with -2

2. Mertsj

Is the x in your post missing its exponent?

3. KrystaRenee

I have already but I keep getting an answer that is not on my option list..

4. Mertsj

So what is the exponent on the x?

5. KrystaRenee

What?

6. Mertsj

$2x ^{-2}y ^{-2}$

7. Mertsj

8. KrystaRenee

Yes.

9. Mertsj

So rewrite it with positive exponents.

10. KrystaRenee

Do you mean change the -2's to positive 2's?

11. Mertsj

yes

12. KrystaRenee

So 72?

13. Mertsj

$\frac{2}{x^2}-\frac{2}{y^2}=\frac{2}{(3)^2}-\frac{2}{(-2)^2}$

14. Mertsj

Can you finish that?

15. KrystaRenee

I have no idea how to. I just started this class.

16. Mertsj

Is there parentheses around anything in the original problem?

17. KrystaRenee

Nope.

18. Mertsj

$2x ^{-2}y ^{-2}=\frac{2}{x^2y^2}=\frac{2}{(3)^2(-2)^2}=\frac{2}{(9)(4)}=\frac{2}{36}=\frac{1}{18}$