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http://roads.advancedacademics.com/contentserver/content/roadssection/279450/questions/assessments/t-righttrianglespythagoreantheoremquiz/geometry_4.3_quiz_8q.gif
Let's get rid of the one triangle that we don't need for this one.

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|dw:1359241647844:dw|
Can you solve that equation for x?
i divide 18 by 2 and get 9 then ill get 9sqrt2
\[x \sqrt{2}=18\]
Divide both sides by sqrt 2
18sqrt2/sqrt 4
\[\frac{x \sqrt{2}}{\sqrt{2}}=\frac{18}{\sqrt{2}}\]
\[x=\frac{18}{\sqrt{2}}\]
Now simplify. Multiply numerator and denominator by sqrt2
i get 18sqrt2/sqrt4 and then i get sqrt18/4
\[\frac{18}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=\frac{18\sqrt{2}}{2}=9\sqrt{2}\]
ohh if a sqrt in on numerator and a other on denominater i can cancell each other
no.

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