anonymous
  • anonymous
simplify each expression :
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1359250931912:dw|
anonymous
  • anonymous
thats to the 1/3 power.
anonymous
  • anonymous
all the numbers are to the power.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[(27p ^{3}q ^{6}r ^{-1})\frac{ ^{1} }{ 3 }\]
Mertsj
  • Mertsj
What is the third root of 27?
anonymous
  • anonymous
sorry about the delay , 3
Mertsj
  • Mertsj
And what is the third root of p^3?
anonymous
  • anonymous
p cubed ?
Mertsj
  • Mertsj
Yes. What is the third root of p cubed?
anonymous
  • anonymous
p ?
Mertsj
  • Mertsj
\[\sqrt[3]{p^{3}}=\]
Mertsj
  • Mertsj
Yes p.
Mertsj
  • Mertsj
What is the third root of p to the sixth?
anonymous
  • anonymous
p?
Mertsj
  • Mertsj
no.
Mertsj
  • Mertsj
\[\sqrt[3]{p^6} =\]
anonymous
  • anonymous
a little help ?
Mertsj
  • Mertsj
\[p ^{\frac{6}{3}}\]
anonymous
  • anonymous
p squared .
Mertsj
  • Mertsj
yes.
anonymous
  • anonymous
okay.
Mertsj
  • Mertsj
When you raise to a power, you multiply the exponents.
anonymous
  • anonymous
okay.
Mertsj
  • Mertsj
\[(27p^3q^6r ^{-1})^{\frac{1}{3}}=3pq^2r ^{-\frac{1}{3}}\]
anonymous
  • anonymous
THANK YOU ! i understood it perfectly. these problems are made seem so hard but you made it so easy !
Mertsj
  • Mertsj
Good for you!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.