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MariaB2014

  • 2 years ago

simplify each expression :

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  1. MariaB2014
    • 2 years ago
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    |dw:1359250931912:dw|

  2. MariaB2014
    • 2 years ago
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    thats to the 1/3 power.

  3. MariaB2014
    • 2 years ago
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    all the numbers are to the power.

  4. MariaB2014
    • 2 years ago
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    \[(27p ^{3}q ^{6}r ^{-1})\frac{ ^{1} }{ 3 }\]

  5. Mertsj
    • 2 years ago
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    What is the third root of 27?

  6. MariaB2014
    • 2 years ago
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    sorry about the delay , 3

  7. Mertsj
    • 2 years ago
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    And what is the third root of p^3?

  8. MariaB2014
    • 2 years ago
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    p cubed ?

  9. Mertsj
    • 2 years ago
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    Yes. What is the third root of p cubed?

  10. MariaB2014
    • 2 years ago
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    p ?

  11. Mertsj
    • 2 years ago
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    \[\sqrt[3]{p^{3}}=\]

  12. Mertsj
    • 2 years ago
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    Yes p.

  13. Mertsj
    • 2 years ago
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    What is the third root of p to the sixth?

  14. MariaB2014
    • 2 years ago
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    p?

  15. Mertsj
    • 2 years ago
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    no.

  16. Mertsj
    • 2 years ago
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    \[\sqrt[3]{p^6} =\]

  17. MariaB2014
    • 2 years ago
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    a little help ?

  18. Mertsj
    • 2 years ago
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    \[p ^{\frac{6}{3}}\]

  19. MariaB2014
    • 2 years ago
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    p squared .

  20. Mertsj
    • 2 years ago
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    yes.

  21. MariaB2014
    • 2 years ago
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    okay.

  22. Mertsj
    • 2 years ago
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    When you raise to a power, you multiply the exponents.

  23. MariaB2014
    • 2 years ago
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    okay.

  24. Mertsj
    • 2 years ago
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    \[(27p^3q^6r ^{-1})^{\frac{1}{3}}=3pq^2r ^{-\frac{1}{3}}\]

  25. MariaB2014
    • 2 years ago
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    THANK YOU ! i understood it perfectly. these problems are made seem so hard but you made it so easy !

  26. Mertsj
    • 2 years ago
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    Good for you!!

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