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LyssaLauren Group Title

Write the standard equation of the circle in the graph. A. (x + 3)squared + (y - 2)squared = 9 B. (x - 3)squared + (y + 2)squared = 9 C. (x - 3)squared + (y + 2)squared = 18 D. (x + 3)squared + (y - 2)squared = 18 Help please! :)

  • one year ago
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  1. LyssaLauren Group Title
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    • one year ago
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  2. campbell_st Group Title
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    the circle centre appears to be (3, -2) and the radius is r = 3 so the general form of a circle is \[(x - h)^2 + (y - k)^2 = r^2\] the centre is (h, k) and r is the radius just substitute the information for the centre and radius into the general equation.

    • one year ago
  3. amoodarya Group Title
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    center of circle is (3,-2) in (3,-2) it is tangent to x-axis so radius =3

    • one year ago
  4. ByteMe Group Title
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    if (h, k) is the center, then the equation is \(\large (x-h)^2+(y-k)^2=r^2 \), where r is the radius plug those values in...

    • one year ago
  5. itsmylife Group Title
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    its B ;)

    • one year ago
  6. LyssaLauren Group Title
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    Thank you guys. :)

    • one year ago
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