Write the standard equation of the circle in the graph. A. (x + 3)squared + (y - 2)squared = 9 B. (x - 3)squared + (y + 2)squared = 9 C. (x - 3)squared + (y + 2)squared = 18 D. (x + 3)squared + (y - 2)squared = 18 Help please! :)

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Write the standard equation of the circle in the graph. A. (x + 3)squared + (y - 2)squared = 9 B. (x - 3)squared + (y + 2)squared = 9 C. (x - 3)squared + (y + 2)squared = 18 D. (x + 3)squared + (y - 2)squared = 18 Help please! :)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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the circle centre appears to be (3, -2) and the radius is r = 3 so the general form of a circle is \[(x - h)^2 + (y - k)^2 = r^2\] the centre is (h, k) and r is the radius just substitute the information for the centre and radius into the general equation.
center of circle is (3,-2) in (3,-2) it is tangent to x-axis so radius =3

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if (h, k) is the center, then the equation is \(\large (x-h)^2+(y-k)^2=r^2 \), where r is the radius plug those values in...
its B ;)
Thank you guys. :)

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