At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

I believe so, yes...

yes yes yes.

And so, if they do not span \(\Re^3\), they are linearly dependent, right?

yeah three vectors that aren't all linearly independent cannot span \[\mathbb R^3\]

i wouldn't word it like that

thats is better yes

That's pretty nice :) Thanks!
May I ask one more question about linear dependence here?

sure

\(\vec{v}\) **

if you find the angle between vectors is π/2 the vectors will be independent

How to find the angle between three vectors??

\[\theta=\arccos\left(\frac{\vec u \cdot \vec v}{||\vec u||~~||\vec v||}\right)\]

For multiple vectors you would have to find the angle between each possible pair of vectors

For the case of two vectors, I still can do it. But not for three or more vectors..