anonymous
  • anonymous
Write an equation for a line parallel to 12+8x=-3y and passing through (3,-5)
Algebra
schrodinger
  • schrodinger
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mathstudent55
  • mathstudent55
Ready?
anonymous
  • anonymous
Yes:)
mathstudent55
  • mathstudent55
This is the same idea. You need a line parallel to a given line. Parallel lines have the same slope. So the first job is to find the slope of the given line. To do that, you solve the equation for y. First, switch sides. -3y = ...

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anonymous
  • anonymous
-3y=8x+12
mathstudent55
  • mathstudent55
Good. Second job, what is happening to y?
anonymous
  • anonymous
umm will be dividing -3y to 8x and 12??
mathstudent55
  • mathstudent55
Yes, you divide every term on both sides by -3 to undo the y being multiplied by -3.
anonymous
  • anonymous
That will end up being y=-8/3-4 ?
mathstudent55
  • mathstudent55
remember the x on the right side. |dw:1359264332902:dw|
mathstudent55
  • mathstudent55
|dw:1359264433972:dw|
anonymous
  • anonymous
YAY! I was correct so then I will need to plug in (3,-5) right?
mathstudent55
  • mathstudent55
Now you know the slope you need is m = ?
anonymous
  • anonymous
m=-8/3
mathstudent55
  • mathstudent55
Great. Now the new equation is going to have m = -8/3, and point (3, -5) If you plug in -8/3 for m and 3 for x and -5 for y into y = mx + b, you can solve for b.
anonymous
  • anonymous
b will equal to 3(:
mathstudent55
  • mathstudent55
|dw:1359264870692:dw|
mathstudent55
  • mathstudent55
Since you now know m and b, what is the equation of the new line?
anonymous
  • anonymous
~le dances~ The equation will be y=-8/3+3 =D
mathstudent55
  • mathstudent55
That is it! Great work again!
anonymous
  • anonymous
THANK YOU SO MUCH FOR YOUR GREAT TUTORING! YOUR AMAZING=D=D
mathstudent55
  • mathstudent55
Thanks. You're not so bad yourself. :-)

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