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ineedyouubiebs

  • 2 years ago

Write an equation for a line parallel to 12+8x=-3y and passing through (3,-5)

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  1. mathstudent55
    • 2 years ago
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    Ready?

  2. ineedyouubiebs
    • 2 years ago
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    Yes:)

  3. mathstudent55
    • 2 years ago
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    This is the same idea. You need a line parallel to a given line. Parallel lines have the same slope. So the first job is to find the slope of the given line. To do that, you solve the equation for y. First, switch sides. -3y = ...

  4. ineedyouubiebs
    • 2 years ago
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    -3y=8x+12

  5. mathstudent55
    • 2 years ago
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    Good. Second job, what is happening to y?

  6. ineedyouubiebs
    • 2 years ago
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    umm will be dividing -3y to 8x and 12??

  7. mathstudent55
    • 2 years ago
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    Yes, you divide every term on both sides by -3 to undo the y being multiplied by -3.

  8. ineedyouubiebs
    • 2 years ago
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    That will end up being y=-8/3-4 ?

  9. mathstudent55
    • 2 years ago
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    remember the x on the right side. |dw:1359264332902:dw|

  10. mathstudent55
    • 2 years ago
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    |dw:1359264433972:dw|

  11. ineedyouubiebs
    • 2 years ago
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    YAY! I was correct so then I will need to plug in (3,-5) right?

  12. mathstudent55
    • 2 years ago
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    Now you know the slope you need is m = ?

  13. ineedyouubiebs
    • 2 years ago
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    m=-8/3

  14. mathstudent55
    • 2 years ago
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    Great. Now the new equation is going to have m = -8/3, and point (3, -5) If you plug in -8/3 for m and 3 for x and -5 for y into y = mx + b, you can solve for b.

  15. ineedyouubiebs
    • 2 years ago
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    b will equal to 3(:

  16. mathstudent55
    • 2 years ago
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    |dw:1359264870692:dw|

  17. mathstudent55
    • 2 years ago
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    Since you now know m and b, what is the equation of the new line?

  18. ineedyouubiebs
    • 2 years ago
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    ~le dances~ The equation will be y=-8/3+3 =D

  19. mathstudent55
    • 2 years ago
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    That is it! Great work again!

  20. ineedyouubiebs
    • 2 years ago
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    THANK YOU SO MUCH FOR YOUR GREAT TUTORING! YOUR AMAZING=D=D

  21. mathstudent55
    • 2 years ago
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    Thanks. You're not so bad yourself. :-)

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