ineedyouubiebs
Write an equation for a line parallel to 12+8x=-3y and passing through (3,-5)
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mathstudent55
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Ready?
ineedyouubiebs
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Yes:)
mathstudent55
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This is the same idea. You need a line parallel to a given line. Parallel lines have the same slope. So the first job is to find the slope of the given line.
To do that, you solve the equation for y.
First, switch sides.
-3y = ...
ineedyouubiebs
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-3y=8x+12
mathstudent55
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Good. Second job, what is happening to y?
ineedyouubiebs
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umm will be dividing -3y to 8x and 12??
mathstudent55
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Yes, you divide every term on both sides by -3 to undo the y being multiplied by -3.
ineedyouubiebs
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That will end up being y=-8/3-4 ?
mathstudent55
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remember the x on the right side.
|dw:1359264332902:dw|
mathstudent55
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|dw:1359264433972:dw|
ineedyouubiebs
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YAY! I was correct so then I will need to plug in (3,-5) right?
mathstudent55
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Now you know the slope you need is m = ?
ineedyouubiebs
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m=-8/3
mathstudent55
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Great.
Now the new equation is going to have m = -8/3, and point (3, -5)
If you plug in -8/3 for m and 3 for x and -5 for y into
y = mx + b, you can solve for b.
ineedyouubiebs
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b will equal to 3(:
mathstudent55
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|dw:1359264870692:dw|
mathstudent55
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Since you now know m and b, what is the equation of the new line?
ineedyouubiebs
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~le dances~ The equation will be y=-8/3+3 =D
mathstudent55
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That is it! Great work again!
ineedyouubiebs
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THANK YOU SO MUCH FOR YOUR GREAT TUTORING! YOUR AMAZING=D=D
mathstudent55
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Thanks. You're not so bad yourself. :-)