## ineedyouubiebs 2 years ago Write an equation for a line parallel to 12+8x=-3y and passing through (3,-5)

1. mathstudent55

2. ineedyouubiebs

Yes:)

3. mathstudent55

This is the same idea. You need a line parallel to a given line. Parallel lines have the same slope. So the first job is to find the slope of the given line. To do that, you solve the equation for y. First, switch sides. -3y = ...

4. ineedyouubiebs

-3y=8x+12

5. mathstudent55

Good. Second job, what is happening to y?

6. ineedyouubiebs

umm will be dividing -3y to 8x and 12??

7. mathstudent55

Yes, you divide every term on both sides by -3 to undo the y being multiplied by -3.

8. ineedyouubiebs

That will end up being y=-8/3-4 ?

9. mathstudent55

remember the x on the right side. |dw:1359264332902:dw|

10. mathstudent55

|dw:1359264433972:dw|

11. ineedyouubiebs

YAY! I was correct so then I will need to plug in (3,-5) right?

12. mathstudent55

Now you know the slope you need is m = ?

13. ineedyouubiebs

m=-8/3

14. mathstudent55

Great. Now the new equation is going to have m = -8/3, and point (3, -5) If you plug in -8/3 for m and 3 for x and -5 for y into y = mx + b, you can solve for b.

15. ineedyouubiebs

b will equal to 3(:

16. mathstudent55

|dw:1359264870692:dw|

17. mathstudent55

Since you now know m and b, what is the equation of the new line?

18. ineedyouubiebs

~le dances~ The equation will be y=-8/3+3 =D

19. mathstudent55

That is it! Great work again!

20. ineedyouubiebs