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Jaweria
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I need help with 11 questions of Derivatives problems in Calculus 1. Can anyone help me with that please let me know, I will really appreciate it.
 one year ago
 one year ago
Jaweria Group Title
I need help with 11 questions of Derivatives problems in Calculus 1. Can anyone help me with that please let me know, I will really appreciate it.
 one year ago
 one year ago

This Question is Closed

AravindG Group TitleBest ResponseYou've already chosen the best response.1
we cant help with all 11 .maybe we can help in 1 or 2 with fond hope that you will understand how to do these and finish the rest yourself.
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
hmm thanks ok i ll need your help with atleast 2 of them.
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
bring it on !! and "WELCOME TO OPENSTUDY!!"
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
one of them is : dw:1359270057247:dw
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
thank you :)
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
and we are finding dx/dy
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
ok diff both sides with respect to y
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
use product rule
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
Like this:dw:1359270336745:dw
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
not sure though
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
can anyone help me here with my questions?
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
its \[x ^{2}y ^{2}=1 \] or \[xy ^{2}=1\]?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
its x\[its x ^{2}y ^{2}=1\]
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
OK....differentiate both sides wrt to y using product rule:: \[x ^{2}(2y)+((y ^{2})2x (dx/dy))=0\]
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
sorry i gt disconnected :O
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
so tell me from above equation what would be dx/dy?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
oh its ok AravindG
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
ok i will tell you
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
just solve for dx/dy after you applied product rule which will be .....
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
I need little bit of more discription for that if its possible.
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
everybody left me here :(
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
no one wants to help me :(
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
\[y^2=\frac{ 1 }{ x^2 }\]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
\[y^2=x^{2}\]
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
how did you get \[X ^{2}\]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Do you know how to differentiate explicitly?
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
You don't know that ???? \[x^2=\frac{1}{x^2}\]
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
oh yeah i do sorry
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
So now, do you know how to differentiate explicitly?
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
That means you differentiate boths sides at the same time.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Okay. Give it a shot and tell me what you get. Remember, when you differentiate the y part, you also have to attach a dy/dx.
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
is it \[\frac{ y }{ x}\]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Nope. Show me what you did as your first step.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
I gave you this to differentiate. \[y^2=x^{2}\]
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
I did like this:dw:1359271872658:dw
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Then what's your next step.
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
then I canceled \[Y ^{2} which became Y and Then I can canceled X ^{2} and \it became x\]
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
oppss sorry i did bad
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
u have any doubt in my way......should i explain?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
lolz right now I dont have any doubt at anyone I just need help very badly :(
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
When you differentiate y^2, you get 2y?
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Why did you get y?
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
and when you differentiate x^{2}, you get 2x^{3}
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
why did you get x?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
Yes I did a mistake for X though but I couldnt understand Y one
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
differentiate x^2
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
That's exactly the same as differentiating y^2. What are you doing?
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
\[2y\times \frac{ dy }{ dx }=\frac{ 2 }{ x^3 }\]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Make dy/dx the subject.
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
sorry one question that why there is
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
Sorry but i have a question that how you got X^3
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
\[(2x ^{2}y)=(2xy ^{2})(dx/dy)\] \[dx/dy=(2x ^{2}y)/(2xy ^{2})\] dx/dy=x/y
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=differentiate+y%5E2%3Dx%5E2
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
thanks Nitz for this :)
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
Aztec actually the answer I am having from the professor is matching with Nitz
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
@Jaweria, do you have an answer sheet or something?
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Ah okay. I can see that because you differentiate straight away. I moved the x^2 to the other side. Somehow that affected it.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
nitz just differentiate straight away using the product rule.
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
but as Nitz just explained I am little bit confused there that how he is getting 2\[2X ^{2}Y\] isnt that when you get 2X then you dont need \[2X ^{2}\]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Don't you know how to do the product rule?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
I have it on my notes and I am still trying to learn this is my first homework of this Calculus class
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
I found it hard
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
What's the answer say in your sheet, Does it say x/y or y/x?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
it says \[\frac{ y }{ x }\]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Nitz is wrong then...
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
<Look at his answer.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
He did dx/dy. You want dy/dx
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
yeah but I dont think so that really matters you can do either way
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
so its just we are flipping dy/dx instead of dx/dy
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
here's how you get y/x
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
\[u=x^2\] \[u'=2x\] \[v=y^2\] \[v'=2y\] \[\frac{ dy }{ dx }=(u'\times v)+(u\times v')\]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Sorry about that. \[0=2xy^2+2x^2y(\frac{dy}{dx})\]
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
When you differentiate y^2 you would write dy/dx next to it.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Then you make dy/dx as the subject.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
And you're done.
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
ahan cool thanks.
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
No worries mate.
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
one last question plzz
 one year ago

Azteck Group TitleBest ResponseYou've already chosen the best response.1
Okay. last one. And you can try and finish the others yourself using what you got from here.
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
\[y ^{2}\tan(x)=x\]
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
to find dx/dy ?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
product rule on left
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
try using draw button i will check :)
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
I know I ll get stuck again :( but I am trying
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
try ! try you will succeed ! :)
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
alright :)
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
ok first step so far: dw:1359274476783:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
can you write thhird term again ? i cant see it clearly
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
dw:1359274789970:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
i mean third term fully from y^2 sec^2 x
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
oh ok sorry
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
and why do you have 2 equal signs ?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
dw:1359274989073:dw
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
I put X after equal sign because thats also in the question
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
for x diff with respect to y it will be simply dx/dy isnt it?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
yeah thats what I pot in paranthesis next to the X
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
you wrote dy/dx there?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
yes next to it
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
dw:1359275398794:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
what was the question ?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
what i think is your question is \[y^2 \tan(x)=x \]
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
\[Y ^{2}\tan (x)=x\]
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
dw:1359275616596:dw
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
this is what i get
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
sorry what is equal to dy/dx?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
nothing !!
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
we just diff with respect to dy the whole equation
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
so why do you think dy/dx will appear?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
so the way i did is that wrong?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
if you wanted dx/dy I believe my method is enough ...
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
i will be glad if someone verifies this bcoz i have not done differentiation for a while :P
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
is Aztec here?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
dunno , maybe he is away
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
have patience :) in the meantime try to work on other questions .BEST OF LUCK !
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
i have an answer sheet though
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
alright then i ll work on them :)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
ok whats the answer you have for this question ?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
its \[(1y ^{2}\sec ^{2}x)/2y \tan (x)\]
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
in btw i frgt to add tan x here dw:1359276176708:dw
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
ahan thats what I was thinking
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
i get dx/dy as reciprocal of your answer...are you sure the question asks for dx/dy ?
 one year ago

Jaweria Group TitleBest ResponseYou've already chosen the best response.1
nope its asking for dy/dx
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
then my working is right !! :)
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
solve for dx/dy from my working...dy/dx=1/dx/dy
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
understood?
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.1
Ok bye I gtg
 one year ago
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