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Jaweria
 3 years ago
I need help with 11 questions of Derivatives problems in Calculus 1. Can anyone help me with that please let me know, I will really appreciate it.
Jaweria
 3 years ago
I need help with 11 questions of Derivatives problems in Calculus 1. Can anyone help me with that please let me know, I will really appreciate it.

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AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1we cant help with all 11 .maybe we can help in 1 or 2 with fond hope that you will understand how to do these and finish the rest yourself.

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1hmm thanks ok i ll need your help with atleast 2 of them.

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1bring it on !! and "WELCOME TO OPENSTUDY!!"

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1one of them is : dw:1359270057247:dw

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1and we are finding dx/dy

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1ok diff both sides with respect to y

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1Like this:dw:1359270336745:dw

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1can anyone help me here with my questions?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its \[x ^{2}y ^{2}=1 \] or \[xy ^{2}=1\]?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1its x\[its x ^{2}y ^{2}=1\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0OK....differentiate both sides wrt to y using product rule:: \[x ^{2}(2y)+((y ^{2})2x (dx/dy))=0\]

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1sorry i gt disconnected :O

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so tell me from above equation what would be dx/dy?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1just solve for dx/dy after you applied product rule which will be .....

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1I need little bit of more discription for that if its possible.

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1everybody left me here :(

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1no one wants to help me :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[y^2=\frac{ 1 }{ x^2 }\]

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1how did you get \[X ^{2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know how to differentiate explicitly?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You don't know that ???? \[x^2=\frac{1}{x^2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So now, do you know how to differentiate explicitly?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That means you differentiate boths sides at the same time.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay. Give it a shot and tell me what you get. Remember, when you differentiate the y part, you also have to attach a dy/dx.

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1is it \[\frac{ y }{ x}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Nope. Show me what you did as your first step.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I gave you this to differentiate. \[y^2=x^{2}\]

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1I did like this:dw:1359271872658:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Then what's your next step.

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1then I canceled \[Y ^{2} which became Y and Then I can canceled X ^{2} and \it became x\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0u have any doubt in my way......should i explain?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1lolz right now I dont have any doubt at anyone I just need help very badly :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0When you differentiate y^2, you get 2y?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and when you differentiate x^{2}, you get 2x^{3}

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1Yes I did a mistake for X though but I couldnt understand Y one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That's exactly the same as differentiating y^2. What are you doing?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[2y\times \frac{ dy }{ dx }=\frac{ 2 }{ x^3 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Make dy/dx the subject.

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1sorry one question that why there is

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry but i have a question that how you got X^3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[(2x ^{2}y)=(2xy ^{2})(dx/dy)\] \[dx/dy=(2x ^{2}y)/(2xy ^{2})\] dx/dy=x/y

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=differentiate+y%5E2%3Dx%5E2

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1thanks Nitz for this :)

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1Aztec actually the answer I am having from the professor is matching with Nitz

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Jaweria, do you have an answer sheet or something?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ah okay. I can see that because you differentiate straight away. I moved the x^2 to the other side. Somehow that affected it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nitz just differentiate straight away using the product rule.

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1but as Nitz just explained I am little bit confused there that how he is getting 2\[2X ^{2}Y\] isnt that when you get 2X then you dont need \[2X ^{2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Don't you know how to do the product rule?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1I have it on my notes and I am still trying to learn this is my first homework of this Calculus class

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What's the answer say in your sheet, Does it say x/y or y/x?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1it says \[\frac{ y }{ x }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Nitz is wrong then...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0He did dx/dy. You want dy/dx

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1yeah but I dont think so that really matters you can do either way

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1so its just we are flipping dy/dx instead of dx/dy

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here's how you get y/x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[u=x^2\] \[u'=2x\] \[v=y^2\] \[v'=2y\] \[\frac{ dy }{ dx }=(u'\times v)+(u\times v')\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry about that. \[0=2xy^2+2x^2y(\frac{dy}{dx})\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0When you differentiate y^2 you would write dy/dx next to it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Then you make dy/dx as the subject.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay. last one. And you can try and finish the others yourself using what you got from here.

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1try using draw button i will check :)

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1I know I ll get stuck again :( but I am trying

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1try ! try you will succeed ! :)

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1ok first step so far: dw:1359274476783:dw

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1can you write thhird term again ? i cant see it clearly

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1i mean third term fully from y^2 sec^2 x

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1and why do you have 2 equal signs ?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1I put X after equal sign because thats also in the question

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1for x diff with respect to y it will be simply dx/dy isnt it?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1yeah thats what I pot in paranthesis next to the X

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1you wrote dy/dx there?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1what was the question ?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1what i think is your question is \[y^2 \tan(x)=x \]

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1sorry what is equal to dy/dx?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1we just diff with respect to dy the whole equation

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1so why do you think dy/dx will appear?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1so the way i did is that wrong?

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1if you wanted dx/dy I believe my method is enough ...

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1i will be glad if someone verifies this bcoz i have not done differentiation for a while :P

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1dunno , maybe he is away

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1have patience :) in the meantime try to work on other questions .BEST OF LUCK !

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1i have an answer sheet though

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1alright then i ll work on them :)

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1ok whats the answer you have for this question ?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1its \[(1y ^{2}\sec ^{2}x)/2y \tan (x)\]

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1in btw i frgt to add tan x here dw:1359276176708:dw

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1ahan thats what I was thinking

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1i get dx/dy as reciprocal of your answer...are you sure the question asks for dx/dy ?

jaweria
 3 years ago
Best ResponseYou've already chosen the best response.1nope its asking for dy/dx

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1then my working is right !! :)

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.1solve for dx/dy from my working...dy/dx=1/dx/dy
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