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treydwg
 2 years ago
Best ResponseYou've already chosen the best response.0Can I factor this by grouping? 25b^2+10b+1?

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0Prime factors of 25 are 5 and 5 so we'll have (5x + a)(5x+b). Multiply that out and you get \[(5x+a)(5x+b) = 25x^2 + 5ax + 5bx + ab\] To make that look like your equation, a and b have to = 1.

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.125b^2+10b+1 multiply 25 with 1 you will get 25. now write 10 as the sum of two numbers such that the addition of those numbers result in 10 and the product of those numbers result in 25

treydwg
 2 years ago
Best ResponseYou've already chosen the best response.0I got b(5b+1) 1(b+1) but that does not look correct?

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0No, (5b+1)(5b+1) is what you want.

chmvijay
 2 years ago
Best ResponseYou've already chosen the best response.0(5b+1) and (5b+1) you correct it once again

treydwg
 2 years ago
Best ResponseYou've already chosen the best response.0t(4t+1)=0? I got t=0, 1/4

Hero
 2 years ago
Best ResponseYou've already chosen the best response.1Well, no one really did it the correct way.

rizwan_uet
 2 years ago
Best ResponseYou've already chosen the best response.125b^2+10b+1 25b^2 +5b+5b+1 5b(5b+1)+1(5b+1) (5b+1)(5b+1) (5b+1)^2

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0No, some of us did it in a way that shows why grouping works :)

chmvijay
 2 years ago
Best ResponseYou've already chosen the best response.025b25b+5b+1=0 5(5b+1)+1(5b+1)=0 (5b+1)2=0 5b+1=0 5b=1 b=1/5

Hero
 2 years ago
Best ResponseYou've already chosen the best response.1Yes, but you forgot to show the process, which is also important as well @whpalmer4. The question was "How do you factor by grouping?". Showing why it works is fine. Showing the process is equally important.
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