anonymous
  • anonymous
Can I factor this by grouping?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
25b^2+10b+1?
anonymous
  • anonymous
Can I factor this by grouping? 25b^2+10b+1?
chmvijay
  • chmvijay
5b+1

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More answers

chmvijay
  • chmvijay
b=-1/5
whpalmer4
  • whpalmer4
Prime factors of 25 are 5 and 5 so we'll have (5x + a)(5x+b). Multiply that out and you get \[(5x+a)(5x+b) = 25x^2 + 5ax + 5bx + ab\] To make that look like your equation, a and b have to = 1.
anonymous
  • anonymous
25b^2+10b+1 multiply 25 with 1 you will get 25. now write 10 as the sum of two numbers such that the addition of those numbers result in 10 and the product of those numbers result in 25
anonymous
  • anonymous
I got b(5b+1) 1(b+1) but that does not look correct?
whpalmer4
  • whpalmer4
No, (5b+1)(5b+1) is what you want.
chmvijay
  • chmvijay
(5b+1) and (5b+1) you correct it once again
anonymous
  • anonymous
5b+1)^2?
anonymous
  • anonymous
yes...
anonymous
  • anonymous
Thanks
anonymous
  • anonymous
t(4t+1)=0? I got t=0, -1/4
anonymous
  • anonymous
ya
anonymous
  • anonymous
Alright cool! Thanks
anonymous
  • anonymous
welcome......
Hero
  • Hero
Well, no one really did it the correct way.
anonymous
  • anonymous
25b^2+10b+1 25b^2 +5b+5b+1 5b(5b+1)+1(5b+1) (5b+1)(5b+1) (5b+1)^2
whpalmer4
  • whpalmer4
No, some of us did it in a way that shows why grouping works :-)
chmvijay
  • chmvijay
25b25b+5b+1=0 5(5b+1)+1(5b+1)=0 (5b+1)2=0 5b+1=0 5b=-1 b=-1/5
Hero
  • Hero
Yes, but you forgot to show the process, which is also important as well @whpalmer4. The question was "How do you factor by grouping?". Showing why it works is fine. Showing the process is equally important.

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