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treydwgBest ResponseYou've already chosen the best response.0
Can I factor this by grouping? 25b^2+10b+1?
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
Prime factors of 25 are 5 and 5 so we'll have (5x + a)(5x+b). Multiply that out and you get \[(5x+a)(5x+b) = 25x^2 + 5ax + 5bx + ab\] To make that look like your equation, a and b have to = 1.
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
25b^2+10b+1 multiply 25 with 1 you will get 25. now write 10 as the sum of two numbers such that the addition of those numbers result in 10 and the product of those numbers result in 25
 one year ago

treydwgBest ResponseYou've already chosen the best response.0
I got b(5b+1) 1(b+1) but that does not look correct?
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
No, (5b+1)(5b+1) is what you want.
 one year ago

chmvijayBest ResponseYou've already chosen the best response.0
(5b+1) and (5b+1) you correct it once again
 one year ago

treydwgBest ResponseYou've already chosen the best response.0
t(4t+1)=0? I got t=0, 1/4
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Well, no one really did it the correct way.
 one year ago

rizwan_uetBest ResponseYou've already chosen the best response.1
25b^2+10b+1 25b^2 +5b+5b+1 5b(5b+1)+1(5b+1) (5b+1)(5b+1) (5b+1)^2
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.0
No, some of us did it in a way that shows why grouping works :)
 one year ago

chmvijayBest ResponseYou've already chosen the best response.0
25b25b+5b+1=0 5(5b+1)+1(5b+1)=0 (5b+1)2=0 5b+1=0 5b=1 b=1/5
 one year ago

HeroBest ResponseYou've already chosen the best response.1
Yes, but you forgot to show the process, which is also important as well @whpalmer4. The question was "How do you factor by grouping?". Showing why it works is fine. Showing the process is equally important.
 one year ago
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